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1828 United States presidential election in Illinois

From Wikipedia, the free encyclopedia

United States presidential election in Illinois, 1828

← 1824 October 31 – December 2, 1828 1832 →
 
Andrew Jackson.jpg
JohnQAdams.jpg
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 3 0
Popular vote 9,560 4,662
Percentage 67.22% 32.78%

The 1828 United States presidential election in Illinois took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Illinois voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Illinois by a margin of 34.44%.

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  • ✪ The American Presidential Election of 2008
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  • ✪ The American Presidential Election of 1928
  • ✪ The American Presidential Election of 1852
  • ✪ The American Presidential Election of 1884

Transcription

Results

United States presidential election in Illinois, 1828[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 9,560 67.22% 3
National Republican John Quincy Adams 4,662 32.78% 0
Totals 14,222 100.0% 3

References

  1. ^ "1828 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved 28 February 2013.


This page was last edited on 26 June 2019, at 21:17
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