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1864 United States presidential election in Illinois

From Wikipedia, the free encyclopedia

1864 United States presidential election in Illinois

← 1860 November 8, 1864 1868 →
Turnout20.34% of the total population Increase 0.50 pp[1]
Abraham Lincoln November 1863.jpg
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois Pennsylvania
Running mate Andrew Johnson George H. Pendleton
Electoral vote 16 0
Popular vote 189,512 158,724
Percentage 54.42% 45.58%

President before election

Abraham Lincoln

Elected President

Abraham Lincoln

The 1864 United States presidential election in Illinois took place on November 8, 1864, as part of the 1864 United States presidential election. Illinois voters chose sixteen representatives, or electors, to the Electoral College, who voted for president and vice president.[2]

Illinois was won by the incumbent President Abraham Lincoln (R-Illinois), running with former Senator and Military Governor of Tennessee Andrew Johnson, with 54.42% of the popular vote, against the 4th Commanding General of the United States Army George B. McClellan (DPennsylvania), running with Representative George H. Pendleton, with 45.58% of the vote.[2]

YouTube Encyclopedic

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  • ✪ The American Presidential Election of 1860
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  • ✪ Illinois Adventure #1406 "Old State Capitol"
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1864 United States presidential election in Illinois[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
National Union Abraham Lincoln of Illinois Andrew Johnson of Tennessee 189,512 54.42% 16 100.00%
Democratic George B. McClellan of Pennsylvania George H. Pendleton of Ohio 158,724 45.58% 0 0.00%
Total 348,236 100.00% 16 100.00%


  1. ^ "1880 Presidential Election Results Illinois Total Population Turnout".
  2. ^ a b c "1864 Presidential Election Results Illinois".

This page was last edited on 21 January 2020, at 19:24
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