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1828 United States presidential election in New Jersey

From Wikipedia, the free encyclopedia

1828 United States presidential election in New Jersey

← 1824 October 31 – December 2, 1828 1832 →
 
JohnQAdams.jpg
Andrew Jackson.jpg
Nominee John Quincy Adams Andrew Jackson
Party National Republican Democratic
Home state Massachusetts Tennessee
Running mate Richard Rush John C. Calhoun
Electoral vote 8 0
Popular vote 23,753 21,809
Percentage 52.12% 47.86%

The 1828 United States presidential election in New Jersey took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.

New Jersey voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won New Jersey by a margin of 4.26%.

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Transcription

Results

1828 United States presidential election in New Jersey[1]
Party Candidate Votes Percentage Electoral votes
National Republican John Quincy Adams 23,753 52.12% 8
Democratic Andrew Jackson 21,809 47.86% 0
N/A Other 8 0.02% 0
Totals 45,570 100.0% 8

References

  1. ^ "1828 Presidential General Election Results - New Jersey". U.S. Election Atlas. Retrieved 28 February 2013.


This page was last edited on 2 February 2020, at 18:26
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