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1828 United States presidential election in Connecticut

From Wikipedia, the free encyclopedia

1828 United States presidential election in Connecticut

← 1824 October 31 – December 2, 1828 1832 →
 
JohnQAdams.jpg
Andrew Jackson.jpg
Nominee John Quincy Adams Andrew Jackson
Party National Republican Democratic
Home state Massachusetts Tennessee
Running mate Richard Rush John C. Calhoun
Electoral vote 8 0
Popular vote 13,829 4,448
Percentage 71.36% 22.95%

The 1828 United States presidential election in Connecticut took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Connecticut by a margin of 48.41%.

With 71.36% of the popular vote, Connecticut would prove to be Adams' fourth strongest state in the 1828 election after Rhode Island, Massachusetts and Vermont.[1]

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Transcription

Results

1828 United States presidential election in Connecticut[2]
Party Candidate Votes Percentage Electoral votes
National Republican John Quincy Adams 13,829 71.36% 8
Democratic Andrew Jackson 4,448 22.95% 0
N/A Other 1,101 5.68% 0
Totals 19,378 100.0% 8

References

  1. ^ "1828 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ "1828 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 28 February 2013.
This page was last edited on 14 July 2019, at 14:20
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