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1864 United States presidential election in Indiana

From Wikipedia, the free encyclopedia

1864 United States presidential election in Indiana

← 1860 November 8, 1864 1868 →
Abraham Lincoln November 1863.jpg
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 13 0
Popular vote 150,422 130,233
Percentage 53.60% 46.40%

President before election

Abraham Lincoln

Elected President

Abraham Lincoln

The 1864 United States presidential election in Indiana took place on November 8, 1864, as part of the 1864 United States presidential election. Indiana voters chose thirteen representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Indiana was won by the incumbent President Abraham Lincoln (R-Illinois), running with former Senator and Military Governor of Tennessee Andrew Johnson, with 53.60% of the popular vote, against the 4th Commanding General of the United States Army George B. McClellan (DPennsylvania), running with Representative George H. Pendleton, with 46.40% of the vote.[1]


1864 United States presidential election in Indiana[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
National Union Abraham Lincoln of Illinois Andrew Johnson of Tennessee 150,422 53.60% 13 100.00%
Democratic George B. McClellan of Pennsylvania George H. Pendleton of Ohio 130,233 46.40% 0 0.00%
Total 280,655 100.00% 13 100.00%


  1. ^ a b c "1864 Presidential Election Results Indiana".

This page was last edited on 14 November 2020, at 21:15
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