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1824 United States presidential election in Virginia

From Wikipedia, the free encyclopedia

United States presidential election in Virginia, 1824

← 1820 October 26 – December 2, 1824 1828 →
 
WilliamHCrawford.jpg
JohnQAdams.jpg
Andrew Jackson.jpg
Nominee William H. Crawford John Quincy Adams Andrew Jackson
Party Democratic-Republican Democratic-Republican Democratic-Republican
Home state Georgia Massachusetts Tennessee
Running mate Nathaniel Macon John C. Calhoun John C. Calhoun
Electoral vote 24 0 0
Popular vote 8,558 3,419 2,975
Percentage 55.68% 22.24% 19.35%

President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

The 1824 United States presidential election in Virginia took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 24 representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Virginia voted for William H. Crawford over John Quincy Adams, Andrew Jackson, and Henry Clay. Crawford won Virginia by a margin of 33.44%.

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Transcription

Results

United States presidential election in Virginia, 1824[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican William H. Crawford 8,558 55.68% 24
Democratic-Republican John Quincy Adams 3,419 22.24% 0
Democratic-Republican Andrew Jackson 2,975 19.35% 0
Democratic-Republican Henry Clay 419 2.73% 0
Totals 15,371 100.0% 24

References

  1. ^ "1824 Presidential General Election Results - Virginia". U.S. Election Atlas. Retrieved 27 February 2013.


This page was last edited on 1 January 2020, at 19:06
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