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1836 United States presidential election in Virginia

From Wikipedia, the free encyclopedia

United States presidential election in Virginia, 1836

← 1832 November 3 – December 7, 1836 1840 →
 
Van Buren.jpg
HLWhite.jpg
Nominee Martin Van Buren Hugh L. White
Party Democratic Whig
Home state New York Tennessee
Running mate Richard M. Johnson John Tyler
Electoral vote 23 0
Popular vote 30,556 23,384
Percentage 56.64% 43.35%

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

The 1836 United States presidential election in Virginia took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose twenty-three representatives, or electors to the Electoral College, who voted for President and Vice President.

Virginia voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Virginia by a margin of 13.29%.

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Transcription

Results

United States presidential election in Virginia, 1836[1]
Party Candidate Votes Percentage Electoral votes
Democratic Martin Van Buren 30,556 56.64% 23
Whig Hugh L. White 23,384 43.35% 0
Independent Others 5 0.01% 0
Totals 53,945 100.0% 23

References

  1. ^ "1836 Presidential General Election Results - Virginia". U.S. Election Atlas. Retrieved 12 April 2013.


This page was last edited on 2 January 2020, at 03:33
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