To install click the Add extension button. That's it.

The source code for the WIKI 2 extension is being checked by specialists of the Mozilla Foundation, Google, and Apple. You could also do it yourself at any point in time. 4,5
Kelly Slayton
Congratulations on this excellent venture… what a great idea!
Alexander Grigorievskiy
I use WIKI 2 every day and almost forgot how the original Wikipedia looks like.
Live Statistics
English Articles
Improved in 24 Hours
Languages
Recent
Show all languages
What we do. Every page goes through several hundred of perfecting techniques; in live mode. Quite the same Wikipedia. Just better.
.
Leo
Newton
Brights
Milds # Half-logistic distribution

Support Probability density function Cumulative distribution function $k\in [0;\infty )\!$ ${\frac {2e^{-k}}{(1+e^{-k})^{2}}}\!$ ${\frac {1-e^{-k}}{1+e^{-k}}}\!$ $\log _{e}(4)=1.386\ldots$ $\log _{e}(3)=1.0986\ldots$ 0 $\pi ^{2}/3-(\log _{e}(4))^{2}=1.368\ldots$ In probability theory and statistics, the half-logistic distribution is a continuous probability distribution—the distribution of the absolute value of a random variable following the logistic distribution. That is, for

$X=|Y|\!$ where Y is a logistic random variable, X is a half-logistic random variable.

• 1/5
Views:
950 547
41 427
84 953
1 639 672
417 369
• ✪ Why the US' Land is Blocky
• ✪ Lecture 23: Beta distribution | Statistics 110
• ✪ Mean and Variance of Normal Distribution
• ✪ Brazil's Geography Problem
• ✪ An Introduction to the Poisson Distribution

## Specification

### Cumulative distribution function

The cumulative distribution function (cdf) of the half-logistic distribution is intimately related to the cdf of the logistic distribution. Formally, if F(k) is the cdf for the logistic distribution, then G(k) = 2F(k) − 1 is the cdf of a half-logistic distribution. Specifically,

$G(k)={\frac {1-e^{-k}}{1+e^{-k}}}{\text{ for }}k\geq 0.\!$ ### Probability density function

Similarly, the probability density function (pdf) of the half-logistic distribution is g(k) = 2f(k) if f(k) is the pdf of the logistic distribution. Explicitly,

$g(k)={\frac {2e^{-k}}{(1+e^{-k})^{2}}}{\text{ for }}k\geq 0.\!$ Basis of this page is in Wikipedia. Text is available under the CC BY-SA 3.0 Unported License. Non-text media are available under their specified licenses. Wikipedia® is a registered trademark of the Wikimedia Foundation, Inc. WIKI 2 is an independent company and has no affiliation with Wikimedia Foundation.