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1880 United States presidential election in Delaware

From Wikipedia, the free encyclopedia

United States presidential election in Delaware, 1880

← 1876 November 2, 1880 1884 →
Nominee Winfield Scott Hancock James A. Garfield
Party Democratic Republican
Home state Pennsylvania Ohio
Running mate William Hayden English Chester A. Arthur
Electoral vote 3 0
Popular vote 15,181 14,148
Percentage 51.53% 48.03%

President before election

Rutherford B. Hayes

Elected President

James Garfield

The 1880 United States presidential election in Delaware took place on November 2, 1880, as part of the 1880 United States presidential election. Delaware voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Delaware was won by General Winfield Scott Hancock (DPennsylvania), running with former Representative William Hayden English, with 51.53% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 48.03% of the vote.[1]

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United States presidential election in Delaware, 1880[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 15,181 51.53% 3 100.00%
Republican James A. Garfield of Ohio Chester A. Arthur of New York 14,148 48.03% 0 0.00%
Greenback James B. Weaver of Iowa Barzillai J. Chambers of Texas 129 0.44% 0 0.00%
Total 18,345 100.00% 3 100.00%


  1. ^ a b c "1880 Presidential Election Results Delaware".

This page was last edited on 23 December 2019, at 21:22
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