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1876 United States presidential election in Delaware

From Wikipedia, the free encyclopedia

United States presidential election in Delaware, 1876

← 1872 November 7, 1876 1880 →
 
SamuelJonesTilden.png
RutherfordBHayes.png
Nominee Samuel J. Tilden Rutherford B. Hayes
Party Democratic Republican
Home state New York Ohio
Running mate Thomas A. Hendricks William A. Wheeler
Electoral vote 3 0
Popular vote 13,381 10,752
Percentage 55.45% 44.55%

President before election

Ulysses S. Grant
Republican

Elected President

Rutherford B. Hayes
Republican

The 1876 United States presidential election in Delaware took place on November 7, 1876, as part of the 1876 United States presidential election. Delaware voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Delaware was won by Samuel J. Tilden, the former governor of New York (DNew York), running with Thomas A. Hendricks, the governor of Indiana and future vice president, with 55.45% of the popular vote, against Rutherford B. Hayes, the governor of Ohio (R-Ohio), running with Representative William A. Wheeler, with 44.55% of the vote.[1]

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Transcription

Results

United States presidential election in Delaware, 1876[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Samuel J. Tilden of New York Thomas A. Hendricks of Indiana 13,381 55.45% 10 100.00%
Republican Rutherford B. Hayes of Ohio William A. Wheeler of New York 10,752 44.55% 0 0.00%
Total 24,133 100.00% 3 100.00%

References

  1. ^ a b c "1876 Presidential Election Results Delaware".


This page was last edited on 2 August 2019, at 18:14
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