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1792 United States presidential election in Delaware

From Wikipedia, the free encyclopedia

1792 United States presidential election in Delaware

← 1788–89 November 2 – December 5, 1792 1796 →
 
Nominee George Washington John Adams
Party Independent Federalist
Home state Virginia Massachusetts
Electoral vote 3 3
Percentage 100.00%

President before election

George Washington
Independent

Elected President

George Washington
Independent

The 1792 United States presidential election in Delaware took place between November 2 and December 5, 1792 as part of the 1792 United States presidential election. The state legislature chose three members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

Delaware's three electors each cast one vote for the incumbent, George Washington, and one vote for John Adams, the incumbent Vice President.[1]

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Transcription

Results

United States presidential election in Delaware, 1792
Party Candidate Votes Percentage Electoral votes
Independent George Washington (incumbent) 100.00% 3
Totals 100.00% 3

See also

References

  1. ^ 1792 Presidential Electoral Vote Count Dave Leip's Atlas of U.S. Presidential Elections.
This page was last edited on 11 January 2024, at 23:51
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