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1880 United States presidential election in New Jersey

From Wikipedia, the free encyclopedia

1880 United States presidential election in New Jersey

← 1876 November 2, 1880 1884 →
 
WinfieldScottHancock.png
JamesGarfield.png
Nominee Winfield S. Hancock James A. Garfield
Party Democratic Republican
Home state Pennsylvania Ohio
Running mate William H. English Chester A. Arthur
Electoral vote 9 0
Popular vote 122,565 120,555
Percentage 49.84% 49.02%

President before election

Rutherford B. Hayes
Republican

Elected President

James A. Garfield
Republican

The 1880 United States presidential election in New Jersey took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 9 representatives, or electors to the Electoral College, who voted for president and vice president.

New Jersey voted for the Democratic nominee, Winfield Scott Hancock, over the Republican nominee, James A. Garfield. Hancock won the state by a very narrow margin of 0.82%.

The Democratic candidate who loses the popular vote would not win New Jersey again until 2004.

Results

1880 United States presidential election in New Jersey[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 122,565 49.84% 9 100.00%
Republican James Abram Garfield of Ohio Chester Alan Arthur of New York 120,555 49.02% 0 0.00%
Greenback James Baird Weaver of Iowa Barzillai Jefferson Chambers of Texas 2,617 1.06% 0 0.00%
Prohibition Neal Dow of Maine Henry Adams Thompson of Ohio 191 0.08% 0 0.00%
Total 245,928 100.00% 9 100.00%

References

  1. ^ "1880 Presidential General Election Results - New Jersey".


This page was last edited on 2 February 2020, at 18:55
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