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1880 United States presidential election in Missouri

From Wikipedia, the free encyclopedia

1880 United States presidential election in Missouri
← 1876 November 2, 1880 1884 →
 
WinfieldScottHancock.png
JamesGarfield.png
James Weaver - Brady-Handy (cropped).jpg
Nominee Winfield S. Hancock James A. Garfield James B. Weaver
Party Democratic Republican Greenback
Home state Pennsylvania Ohio Iowa
Running mate William H. English Chester A. Arthur Barzillai J. Chambers
Electoral vote 15 0 0
Popular vote 208,600 153,647 35,042
Percentage 52.51% 38.67% 8.82%

Missouri Presidential Election Results 1880.svg
County Results

President before election

Rutherford B. Hayes
Republican

Elected President

James A. Garfield
Republican

The 1880 United States presidential election in Missouri took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.

Missouri voted for the Democratic nominee, Winfield Scott Hancock, over the Republican nominee, James A. Garfield by a margin of 13.83%.

Results

1880 United States presidential election in Missouri[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 208,600 52.51% 15 100.00%
Republican James Abram Garfield of Ohio Chester Alan Arthur of New York 153,647 38.67% 0 0.00%
Greenback James Baird Weaver of Iowa Barzillai Jefferson Chambers of Texas 35,042 8.82% 0 0.00%
Total 397,289 100.00% 15 100.00%

References

  1. ^ "1880 Presidential General Election Results - Missouri".
This page was last edited on 19 February 2021, at 00:39
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