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 County Results
Roosevelt 50-60%
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The 1940 United States presidential election in Delaware took place on November 5, 1940, as part of the 1940 United States presidential election. Delaware voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Delaware was won by incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 54.70% of the popular vote, against Wendell Willkie (R–Indiana), running with Minority Leader Charles L. McNary, with 45.05% of the popular vote.[3][4]
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Transcription
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Franklin D. Roosevelt (inc.) | 74,599 | 54.70% | |
| Republican | Wendell Willkie | 61,440 | 45.05% | |
| Write-in | 335 | 0.25% | ||
| Total votes | 136,334 | 100% | ||
References
- ^ "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved August 20, 2018.
- ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 20, 2018.
- ^ "1940 Presidential General Election Results - Delaware". Retrieved August 20, 2018.
- ^ "The American Presidency Project - Election of 1940". Retrieved August 20, 2018.
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| General articles |
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| Local results |
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| Other 1940 elections | ||
This page was last edited on 15 August 2019, at 07:58