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1880 United States presidential election in Alabama

From Wikipedia, the free encyclopedia

United States presidential election in Alabama, 1880

← 1876 November 2, 1880 1884 →
Turnout12.03% of the total population Decrease 5.19 pp[1]
 
WinfieldScottHancock.png
JamesGarfield.png
Nominee Winfield Scott Hancock James A. Garfield
Party Democratic Republican
Home state Pennsylvania Ohio
Running mate William Hayden English Chester A. Arthur
Electoral vote 10 0
Popular vote 91,130 56,350
Percentage 59.99% 37.10%

Alabama Presidential Election Results by County, 1880.svg
County Results

President before election

Rutherford B. Hayes
Republican

Elected President

James Garfield
Republican

The 1880 United States presidential election in Alabama took place on November 2, 1880, as part of the 1880 United States presidential election. Alabama voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.[2]

Alabama was won by General Winfield Scott Hancock (DPennsylvania), running with former Representative William Hayden English, with 59.99% of the popular vote, against Representative James Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 37.10% of the vote.[2]

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Transcription

Results

United States presidential election in Alabama, 1880[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 91,130 59.99% 10 100.00%
Republican James Garfield of Ohio Chester A. Arthur of New York 56,350 37.10% 0 0.00%
Greenback James B. Weaver of Iowa Barzillai J. Chambers of Texas 4,422 2.91% 0 0.00%
Total 151,902 100.00% 10 100.00%


References

  1. ^ "1884 Presidential Election Results Alabama Total Population Turnout".
  2. ^ a b c "1880 Presidential Election Results Alabama".


This page was last edited on 21 January 2020, at 15:52
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