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1996 United States presidential election in Delaware

From Wikipedia, the free encyclopedia

United States presidential election in Delaware, 1996

← 1992 November 5, 1996 2000 →
Bill Clinton.jpg
Bob Dole, PCCWW photo portrait.JPG
Nominee Bill Clinton Bob Dole Ross Perot
Party Democratic Republican Reform
Home state Arkansas Kansas Texas
Running mate Al Gore Jack Kemp Patrick Choate
Electoral vote 3 0 0
Popular vote 140,355 99,062 28,719
Percentage 51.82% 36.58% 10.60%

Delaware election 1996 map.svg
County Results

President before election

Bill Clinton

Elected President

Bill Clinton

The 1996 United States presidential election in Delaware took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for president and vice president.

Delaware was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 51.82% to 36.58% by a margin of 15.24%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 10.60% of the popular vote.[1] As of the 2016 presidential election, this is the last election in which Sussex County voted for the Democratic candidate.

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United States presidential election in Delaware, 1996
Party Candidate Running mate Votes Percentage Electoral votes
Democratic Bill Clinton (incumbent) Al Gore 140,355 51.82% 3
Republican Bob Dole Jack Kemp 99,062 36.58% 0
Unaffiliated Ross Perot Patrick Choate 28,719 10.60% 0
Libertarian Harry Browne Jo Jorgensen 2,052 0.76% 0
U.S. Taxpayers' Party Howard Phillips Herbert Titus 348 0.13% 0
Natural Law Dr. John Hagelin Mike Tompkins 274 0.10% 0
Write-in Ralph Nader Winona LaDuke 18 0.01% 0
No party Write-in 17 0.01% 0


See also

This page was last edited on 23 December 2019, at 22:52
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