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1852 United States presidential election in Alabama

From Wikipedia, the free encyclopedia

1852 United States presidential election in Alabama

← 1848 November 2, 1852 1856 →
 
Nominee Franklin Pierce Winfield Scott
Party Democratic Whig
Home state New Hampshire New Jersey
Running mate William R. King William A. Graham
Electoral vote 9 0
Popular vote 26,881 15,061
Percentage 60.89% 34.12%

County Results

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

The 1852 United States presidential election in Alabama took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

Alabama voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Alabama by a margin of 26.77%.

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Transcription

Results

1852 United States presidential election in Alabama[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 26,881 60.89% 9 100.00%
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 15,061 34.12% 0 0.00%
Southern Rights George Troup N/A 2,205 4.99% 0 0.00%
Total 44,147 100.00% 9 100.00%

See also

References

  1. ^ "1852 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved December 2, 2017.
  2. ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 2, 2017.


This page was last edited on 26 March 2024, at 00:52
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