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1852 United States presidential election in Ohio

From Wikipedia, the free encyclopedia

1852 United States presidential election in Ohio

← 1848 November 2, 1852 1856 →
 
Mathew Brady - Franklin Pierce crop.jpg
Winfield Scott by Fredricks, 1862 crop.jpg
JP-Hale crop.jpg
Nominee Franklin Pierce Winfield Scott John P. Hale
Party Democratic Whig Free Soil
Home state New Hampshire New Jersey New Hampshire
Running mate William R. King William A. Graham George Washington Julian
Electoral vote 23 0 0
Popular vote 168,933 152,523 31,732
Percentage 47.83% 43.18% 8.98%

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

The 1852 United States presidential election in Ohio was held on November 2, 1852 as part of the 1852 United States presidential election. State voters chose twenty-three electors to the Electoral College, who voted for President and Vice President.

Ohio was narrowly won by the Democratic Party candidate, Franklin Pierce, who won the state a plurality of 47.83% of the popular vote. The Whig Party candidate, Winfield Scott, garnered 43.18% of the popular vote.[1]

Pierce would become the final Democrat to win Ohio until Woodrow Wilson won it in 1912.

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  • ✪ The American Presidential Election of 1852
  • ✪ The American Presidential Election of 1840
  • ✪ The American Presidential Election of 1860
  • ✪ The American Presidential Election of 1888
  • ✪ The American Presidential Election of 1872

Transcription

Results

1852 United States presidential election in Ohio
Party Candidate Votes Percentage Electoral votes
Democratic Franklin Pierce 168,933 47.83% 23
Whig Winfield Scott 152,523 43.18% 0
Free Soil John P. Hale 31,732 8.98% 0
Totals 353,188 100.0% 23

References


This page was last edited on 24 September 2019, at 22:25
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