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1789 New Hampshire gubernatorial election

From Wikipedia, the free encyclopedia

1789 New Hampshire gubernatorial election

← 1788 10 March 1789 1790 →
 
Nominee John Sullivan John Pickering Josiah Bartlett
Party Federalist Anti-Federalist
Popular vote 3,657 3,488 968
Percentage 42.85% 40.87% 11.34%

President before election

John Pickering (Acting)

Elected President

John Sullivan
Federalist

The 1789 New Hampshire gubernatorial election was held on 10 March 1789 in order to elect the President of New Hampshire. (The office would be renamed to Governor in 1792.) Federalist candidate and former President John Sullivan defeated incumbent Acting President John Pickering and 1785 & 1787 President Anti-Federalist candidate Josiah Bartlett. Since no candidate received a majority in the popular vote, Sullivan was elected by the New Hampshire General Court per the state constitution.[1]

General election

On election day, 10 March 1789, Federalist candidate and former President John Sullivan won the popular vote by a margin of 169 votes against his foremost opponent and incumbent Acting President John Pickering. But because no candidate received a majority of the popular vote, a separate election was held by the New Hampshire General Court, which chose Sullivan as the winner. He thereby gained Federalist control over the office of President. Sullivan was sworn in for his third term on 6 June 1789.[2]

Results

New Hampshire gubernatorial election, 1789
Party Candidate Votes %
Federalist John Sullivan 3,657 42.85
John Pickering (incumbent) 3,488 40.87
Anti-Federalist Josiah Bartlett 968 11.34
Scattering 421 4.94
Total votes 8,534 100.00
Federalist gain from Anti-Federalist

References

  1. ^ "John Sullivan". National Governors Association. Retrieved 29 February 2024.
  2. ^ "NH Governor". ourcampaigns.com. 20 January 2012. Retrieved 29 February 2024.
This page was last edited on 31 March 2024, at 23:33
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