Cloverdale, Iowa | |
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  Cloverdale, Iowa Location of Cloverdale, Iowa  Cloverdale, Iowa Cloverdale, Iowa (the United States) | |
| Coordinates: 43°20′49″N 95°41′09″W / 43.3469151°N 95.6858470°W | |
| Country |  United States |
| State |  Iowa |
| County | Osceola County |
| Elevation | 466 m (1,529 ft) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| Zip code | 51249 |
| Area code | 712 |
| GNIS feature ID | 455489 |
Cloverdale is an unincorporated community in Osceola County, Iowa, United States.[1] It is located 5 miles southeast of the county seat Sibley, and 10 miles from the Iowa-Minnesota border. [2]
History
Cloverdale's population was 50 in 1925.[3] The population was also 50 in 1940.[4]
References
- ^ "Report for: Cloverdale". USGNIS. Retrieved October 16, 2017.
- ^ "Osceola County Zoning Map" (PDF). osceolacountyia.org. Retrieved October 16, 2017.
- ^ Company, Rand McNally and (1925). Premier Atlas of the World: Containing Maps of All Countries of the World, with the Most Recent Boundary Decisions, and Maps of All the States,territories, and Possessions of the United States with Population Figures from the Latest Official Census Reports, Also Data of Interest Concerning International and Domestic Political Questions. Rand McNally & Company. p. 190.
- ^ The Attorneys List. United States Fidelity and Guaranty Company, Attorney List Department. 1940. p. 296.
Municipalities and communities of Osceola County, Iowa, United States | ||
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| Cities |  | |
| Townships | ||
| Unincorporated communities | ||
This page was last edited on 9 January 2024, at 05:45