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2018 Moscow River Cup – Doubles

From Wikipedia, the free encyclopedia

This was the first edition of the tournament. Anastasia Potapova and Vera Zvonareva won the title, defeating Alexandra Panova and Galina Voskoboeva in the final, 6–0, 6–3.

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Switzerland X Knoll
Sweden J Larsson
6 6
WC Russia S Lansere
Kazakhstan E Rybakina
2 3 1 Switzerland X Knoll
Sweden J Larsson
6 6
  Montenegro D Kovinić
Russia Y Sizikova
6 77 Montenegro D Kovinić
Russia Y Sizikova
3 1
  Russia E Alexandrova
Russia E Rodina
3 65 1 Switzerland X Knoll
Sweden J Larsson
4 6 [9]
3 Australia M Adamczak
Australia J Moore
64 2 Russia A Panova
Kazakhstan G Voskoboeva
6 2 [11]
  Russia A Panova
Kazakhstan G Voskoboeva
77 6 Russia A Panova
Kazakhstan G Voskoboeva
7 6
  Romania I Bara
Georgia (country) O Kalashnikova
6 1 [13] Romania I Bara
Georgia (country) O Kalashnikova
5 2
WC Russia P Monova
Belgium M Zanevska
3 6 [11] Russia A Panova
Kazakhstan G Voskoboeva
0 3
  Russia A Komardina
United States D Krawczyk
1 6 [7] Russia A Potapova
Russia V Zvonareva
6 6
PR Germany N Geuer
Germany L Siegemund
6 2 [10] PR Germany N Geuer
Germany L Siegemund
78 1 [8]
  Russia A Potapova
Russia V Zvonareva
4 6 [10] Russia A Potapova
Russia V Zvonareva
66 6 [10]
4 Russia N Dzalamidze
Australia An Rodionova
6 3 [6] Russia A Potapova
Russia V Zvonareva
6 77
  Russia A Kalinskaya
Slovakia V Kužmová
3 5 Ukraine K Kozlova
Russia N Vikhlyantseva
3 62
  Ukraine K Kozlova
Russia N Vikhlyantseva
6 7 Ukraine K Kozlova
Russia N Vikhlyantseva
6 7
  Japan R Fujiwara
Croatia D Jurak
6 7 Japan R Fujiwara
Croatia D Jurak
4 5
2 Russia V Kudermetova
Belarus L Marozava
4 5

References

This page was last edited on 20 April 2022, at 14:27
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