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2018 Bucharest Open – Doubles

From Wikipedia, the free encyclopedia

Irina-Camelia Begu and Raluca Olaru were the defending champions, but chose not to participate together. Olaru played alongside Mihaela Buzărnescu, but lost in the semifinals to Danka Kovinić and Maryna Zanevska. Begu teamed up with Andreea Mitu and successfully defended the title, defeating Kovinić and Zanevska in the final, 6–3, 6–4.

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Transcription

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Romania M Buzărnescu
Romania R Olaru
6 6
Russia A Fomina
Kazakhstan E Rybakina
4 2 1 Romania M Buzărnescu
Romania R Olaru
6 6
Spain G García Pérez
Sweden C Lister
7 4 [10] Spain G García Pérez
Sweden C Lister
2 4
Russia N Dzalamidze
Turkey İ Soylu
5 6 [6] 1 Romania M Buzărnescu
Romania R Olaru
4 1
3 Romania I Bara
Germany N Geuer
6 6 Montenegro D Kovinić
Belgium M Zanevska
6 6
Norway U Eikeri
Russia P Leykina
3 4 3 Romania I Bara
Germany N Geuer
1 2
Belgium Y Bonaventure
Georgia (country) O Kalashnikova
4 2 Montenegro D Kovinić
Belgium M Zanevska
6 6
Montenegro D Kovinić
Belgium M Zanevska
6 6 Montenegro D Kovinić
Belgium M Zanevska
3 4
Hungary RL Jani
Slovakia C Škamlová
2 4 WC Romania I-C Begu
Romania A Mitu
6 6
WC Romania I-C Begu
Romania A Mitu
6 6 WC Romania I-C Begu
Romania A Mitu
7 6
Romania A Cadanțu
Argentina M Irigoyen
3 3 4 Belarus L Marozava
Netherlands A Rus
5 2
4 Belarus L Marozava
Netherlands A Rus
6 6 WC Romania I-C Begu
Romania A Mitu
6 3 [10]
Turkey B Eraydın
Russia V Zvonareva
4 1 Romania J Cristian
Romania E-G Ruse
4 6 [6]
Romania J Cristian
Romania E-G Ruse
6 6 Romania J Cristian
Romania E-G Ruse
77 3 [10]
WC Hungary A Bondár
Romania M Bulgaru
4 7 [6] 2 Australia M Adamczak
Australia J Moore
63 6 [4]
2 Australia M Adamczak
Australia J Moore
6 5 [10]

References

This page was last edited on 28 February 2022, at 00:57
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