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Reacting lutetium chloride and alkalis will first produce Lu(OH)2Cl, then it will become Lu(OH)2.5Cl0.5. Finally, the reaction will produce Lu(OH)3.[2]
LuCl3+2 NaOH→Lu(OH)2Cl+2 NaCl
Lu(OH)2Cl+0.5 NaOH→Lu(OH)2.5Cl0.5+0.5 NaCl
Lu(OH)2.5Cl0.5+0.5 NaOH→Lu(OH)3+0.5 NaCl
Chemical properties
Lutetium(III) hydroxide can react with acid and form lutetium(III) salts:
Lu(OH)3 + 3 H+ → Lu3+ + 3 H2O
While heating lutetium(III) hydroxide, it will produce LuO(OH), continued heating could produce Lu2O3.[1]
References
^ abYi, Xianwu; et al. Series of Inorganic Chemistry. Vol 7. Scandium, Rare Earth Elements. Science Press. pp 168-171. (2) Hydroxides.
^Aksel'rud, N. V.; Akhrameeva, T. I. Basic chlorides and hydroxide of lutetium. Zhurnal Neorganicheskoi Khimii, 1962. 7. pp 1998-2001. ISSN0044-457X.