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Campeonato de Australia 1928

De Wikipedia, la enciclopedia libre

Lista de los campeones del Abierto de Australia de 1928:

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Transcription

Individual masculino

Artículo principal:  Abierto de Australia 1928 (individual masculino)

Jean Borotra (FRA) d. Jack Cummings (AUS), 6–4, 6–1, 4–6, 5–7, 6–3

Individual femenino

Artículo principal:  Abierto de Australia 1928 (individual femenino)

Daphne Akhurst (AUS) d. Esna Boyd (AUS), 7–5, 6–2

Dobles masculino

Jean Borotra/Jacques Brugnon (FRA)

Dobles femenino

Artículo principal:  Anexo:Campeonato de Australia 1928 (dobles femenino)

Daphne Akhurst (AUS)/Esna Boyd (AUS)

Dobles mixto

Artículo principal:  Anexo:Campeonato de Australia 1928 (doble mixto)

Daphne Akhurst (AUS)/Jean Borotra (FRA)


Predecesor:
1927 		Abierto de Australia
1928 		Sucesor:
1929
Predecesor:
Campeonato nacional de Estados Unidos 1927 		Grand Slam
1928 		Sucesor:
Torneo de Roland Garros 1928
Esta página se editó por última vez el 24 ene 2024 a las 23:09.
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