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| Elections in Connecticut |
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The 1836 United States presidential election in Connecticut took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
Connecticut voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Connecticut by a narrow margin of 1.3%.
As a result of his win, Van Buren also became the first Democratic presidential candidate to carry Connecticut.
Results
| 1836 United States presidential election in Connecticut[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren | 19,294 | 50.65% | 8 | |
| Whig | William Henry Harrison | 18,799 | 49.35% | 0 | |
| Totals | 38,093 | 100.0% | 8 | ||
See also
References
- ^ "1836 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved August 4, 2012.
State and district results of the 1836 United States presidential election | ||
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This page was last edited on 28 March 2024, at 16:03