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1940 United States Senate election in Vermont

From Wikipedia, the free encyclopedia

1940 United States Senate election in Vermont

← 1934 November 5, 1940 (1940-11-05) 1946 →
 
Austin Warren Robinson.jpg
No image.svg
Nominee Warren Austin Ona Searles
Party Republican Democratic
Popular vote 93,283 47,101
Percentage 66.4% 33.6%

U.S. Senator before election

Warren Austin
Republican

Elected U.S. Senator

Warren Austin
Republican

The 1940 United States Senate election in Vermont took place on November 5, 1940. Incumbent Republican Warren Austin successfully ran for re-election to another term in the United States Senate, defeating Democratic candidate Ona S. Searles. Austin would resign in August 1946 to become United States Ambassador to the United Nations; Ralph Flanders was appointed to replace him and went on to win election to a full term in 1946.

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  • ✪ The American Presidential Election of 1940
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  • ✪ The American Presidential Election of 1936

Transcription

Contents

Republican primary

Results

Republican primary results[1]
Party Candidate Votes % ±
Republican Warren Austin (inc.) 60,603 99.9
Republican Other 65 0.1
Total votes 60,668 100

Democratic primary

Results

Democratic primary results[1]
Party Candidate Votes % ±
Democratic Ona S. Searles 5,340 99.4
Democratic Other 33 0.6
Total votes 5,373 100

General election

Results

United States Senate election in Vermont, 1940[2]
Party Candidate Votes % ±
Republican Warren Austin (inc.) 93,283 66.4
Democratic Ona S. Searles 47,101 33.6
Total votes 140,384 100

See also

References

  1. ^ a b "Primary Election Results" (PDF). Office of the Vermont Secretary of State. Retrieved 16 June 2015.
  2. ^ "General Election Results - U.S. Senator - 1914-2014" (PDF). Office of the Vermont Secretary of State. Retrieved 16 June 2015.
This page was last edited on 19 January 2020, at 09:27
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