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Nonlinear control

From Wikipedia, the free encyclopedia

A feedback control system. It is desired to control a system (often called the plant) so its output follows a desired reference signal. A sensor monitors the output and a controller subtracts the actual output from the desired reference output, and applies this error signal to the system to bring the output closer to the reference. In a nonlinear control system at least one of the blocks, system, sensor, or controller, is nonlinear.

Nonlinear control theory is the area of control theory which deals with systems that are nonlinear, time-variant, or both. Control theory is an interdisciplinary branch of engineering and mathematics that is concerned with the behavior of dynamical systems with inputs, and how to modify the output by changes in the input using feedback, feedforward, or signal filtering. The system to be controlled is called the "plant". One way to make the output of a system follow a desired reference signal is to compare the output of the plant to the desired output, and provide feedback to the plant to modify the output to bring it closer to the desired output.

Control theory is divided into two branches. Linear control theory applies to systems made of devices which obey the superposition principle. They are governed by linear differential equations. A major subclass is systems which in addition have parameters which do not change with time, called linear time invariant (LTI) systems. These systems can be solved by powerful frequency domain mathematical techniques of great generality, such as the Laplace transform, Fourier transform, Z transform, Bode plot, root locus, and Nyquist stability criterion.

Nonlinear control theory covers a wider class of systems that do not obey the superposition principle. It applies to more real-world systems, because all real control systems are nonlinear. These systems are often governed by nonlinear differential equations. The mathematical techniques which have been developed to handle them are more rigorous and much less general, often applying only to narrow categories of systems. These include limit cycle theory, Poincaré maps, Lyapunov stability theory, and describing functions. If only solutions near a stable point are of interest, nonlinear systems can often be linearized by approximating them by a linear system obtained by expanding the nonlinear solution in a series, and then linear techniques can be used.[1] Nonlinear systems are often analyzed using numerical methods on computers, for example by simulating their operation using a simulation language. Even if the plant is linear, a nonlinear controller can often have attractive features such as simpler implementation, faster speed, more accuracy, or reduced control energy, which justify the more difficult design procedure.

An example of a nonlinear control system is a thermostat-controlled heating system. A building heating system such as a furnace has a nonlinear response to changes in temperature; it is either "on" or "off", it does not have the fine control in response to temperature differences that a proportional (linear) device would have. Therefore, the furnace is off until the temperature falls below the "turn on" setpoint of the thermostat, when it turns on. Due to the heat added by the furnace, the temperature increases until it reaches the "turn off" setpoint of the thermostat, which turns the furnace off, and the cycle repeats. This cycling of the temperature about the desired temperature is called a limit cycle, and is characteristic of nonlinear control systems.

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Transcription

Solve the system of equations by graphing. Check your solution algebraically. Let's graph each of these, and let's start-- let me find a nice dark color to graph these with. Let me graph this top equation in blue, this parabola. The first thing to think about is this going to be an upward opening-- one, how did I know it's a parabola? That's because it's a quadratic function: we have an x squared term, a second degree term, here. Then we have to think about: it is going to be upward opening, or downward opening parabola? You see that it's a negative coefficient in front of the x squared, so it's going to be a downward opening parabola. What is going to be its maximum point? Let's think about that for a second. This whole term right here is always going to be negative, or it's always going to be non-positive. x squared will be non-negative when you multiply it by a negative, so it's going to be non-positive. So, the highest value that this thing can take on is when x is going to be equal to 0-- the vertex of this parabola is when x is equal to 0, and y is equal to 6. So, x is equal to 0, and y is 1, 2, 3, 4, 5, 6. So that right there is the highest point of our parabola. Then, if we want, we can a graph a couple of other points, just to see what happens. So let's see what happens when x is equal to-- let me just draw a little table here-- 2, what is y? It's negative x squared plus 6. So when x is 2, what is y? You have 2 squared, which is 4, but you have negative 2 squared, so it's negative 4 plus 6-- it is equal to 2. It's the same thing when x is negative 2. You put negative 2 there, you square it, then you have positive 4, but you have a negative there, so it's negative 4 plus 6 is 2. You have both of those points there, so 2 comma 2, and then you have a negative 2 comma 2. If I were to graph it, Let's try it with 3, as well-- if we put a 3 there, 3 squared is 9. It then becomes a negative 9 plus 3, it becomes negative 3, and negative 3 will also become a negative 3. Negative 3 squared is positive 9, you have a negative out front, it becomes negative 9 plus 6, which is negative 3. You have negative 3, negative 3, and then you have 3, negative 3. So those are all good points. Now we can graph our parabola. Our parabola will look something-- I was doing well until that second part --like that, and let me just do the second part. That second part is hard to draw-- let me do it from here. It looks something like that. We connect to this dot right here, and then let me connect this. So that it looks something like that. That's what our parabola looks like, and obviously it keeps going down in that direction. So that's that first graph. Let's graph this second one over here: y is equal to negative 2x minus 2. This is just going to be a line. It's a linear equation, and the highest degree here is 1. Our y-intercept is negative 2, so 0, 1, 2. Our y-intercept is negative 2. Our slope is negative 2. If we move 1 in the x direction, we're going to go 2 in the y-direction, and if we move 2 in the x direction, we're going to move down 4 in the y direction. If we move back 2, we're going to move up 2 in the y direction, and it looks like we found one of our points of intersection. Let's just draw that line, so that line will look something like-- It's hard for my hand to draw that, but let me try as best as I can. This is the hardest part. It will look something like that right there. The question is, where do they intersect? One point of intersection does immediately pop out at us, because they asked us to do it graphically. That point right there, which is the point negative 2, 2. It seems to pop out at us, so this is the point negative 2, 2. Let's see if that makes sense. When you have the point negative 2, when you put x is equal to negative 2 here, negative 2 times negative 2 is 4 minus 2, and y is equal to 2. When you put negative 2 here, y is also equal to 2, so that makes sense. There's going to be some other point way out here where they also intersect. There's also going to be some other point way out here if we keep making this parabola. When y is equal to positive 4, and you have negative 16 plus 6, you get negative 10. So, positive 1, 2, 3, 4, and then you go down 10. 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. That looks like that might be our other point of intersection, so let me connect this right there. Our other point of intersection looks to be right there. If we just follow this red line it looks like we intersect there. Let's verify that it works out. So 4, negative 10. We know that that's on this blue line, so let's see if it's on this other line. So negative 2 times 4 minus 2, that is negative 8 minus 2, which is equal to negative 10. The point 4, negative 10, is on both of them. When x is equal to 4, y is negative 10 for both equations here, so they both definitely work out.

Properties of nonlinear systems

Some properties of nonlinear dynamic systems are

  • They do not follow the principle of superposition (linearity and homogeneity).
  • They may have multiple isolated equilibrium points.
  • They may exhibit properties such as limit cycle, bifurcation, chaos.
  • Finite escape time: Solutions of nonlinear systems may not exist for all times.

Analysis and control of nonlinear systems

There are several well-developed techniques for analyzing nonlinear feedback systems:

Control design techniques for nonlinear systems also exist. These can be subdivided into techniques which attempt to treat the system as a linear system in a limited range of operation and use (well-known) linear design techniques for each region:

Those that attempt to introduce auxiliary nonlinear feedback in such a way that the system can be treated as linear for purposes of control design:

And Lyapunov based methods:

Nonlinear feedback analysis – The Lur'e problem

Lur'e problem block diagram

An early nonlinear feedback system analysis problem was formulated by A. I. Lur'e. Control systems described by the Lur'e problem have a forward path that is linear and time-invariant, and a feedback path that contains a memory-less, possibly time-varying, static nonlinearity.

The linear part can be characterized by four matrices (A,B,C,D), while the nonlinear part is Φ(y) with (a sector nonlinearity).

Absolute stability problem

Consider:

  1. (A,B) is controllable and (C,A) is observable
  2. two real numbers a, b with a < b, defining a sector for function Φ

The Lur'e problem (also known as the absolute stability problem) is to derive conditions involving only the transfer matrix H(s) and {a,b} such that x = 0 is a globally uniformly asymptotically stable equilibrium of the system.

There are two well-known wrong conjectures on the absolute stability problem:

Graphically, these conjectures can be interpreted in terms of graphical restrictions on the graph of Φ(y) x y or also on the graph of dΦ/dy x Φ/y.[2] There are counterexamples to Aizerman's and Kalman's conjectures such that nonlinearity belongs to the sector of linear stability and unique stable equilibrium coexists with a stable periodic solution—hidden oscillation.

There are two main theorems concerning the Lur'e problem which give sufficient conditions for absolute stability:

Theoretical results in nonlinear control

Frobenius theorem

The Frobenius theorem is a deep result in differential geometry. When applied to nonlinear control, it says the following: Given a system of the form

where , are vector fields belonging to a distribution and are control functions, the integral curves of are restricted to a manifold of dimension if and is an involutive distribution.

See also

References

  1. ^ trim point
  2. ^ Naderi, T.; Materassi, D.; Innocenti, G.; Genesio, R. (2019). "Revisiting Kalman and Aizerman Conjectures via a Graphical Interpretation". IEEE Transactions on Automatic Control. 64 (2): 670–682. doi:10.1109/TAC.2018.2849597. ISSN 0018-9286. S2CID 59553748.

Further reading

External links

This page was last edited on 14 January 2024, at 20:01
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