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Huntington–Hill method

From Wikipedia, the free encyclopedia

The Huntington–Hill method of apportionment assigns seats by finding a modified divisor D such that each constituency's priority quotient (its population divided by D), using the geometric mean of the lower and upper quota for the divisor, yields the correct number of seats that minimizes the percentage differences in the size of subconstituencies.[1] When envisioned as a proportional electoral system, it is effectively a highest averages method of party-list proportional representation in which the divisors are given by , n being the number of seats a state or party is currently allocated in the apportionment process (the lower quota) and n + 1 is the number of seats the state or party would have if it is assigned to the party list (the upper quota). Although no legislature uses this method of apportionment to assign seats to parties after an election, it was considered for House of Lords elections under the ill-fated House of Lords Reform Bill.[2]

The method is how the United States House of Representatives assigns the number of representative seats to each state – the purpose for which it was devised – and the Census Bureau calls it the method of equal proportions.[3] It is credited to Edward Vermilye Huntington and Joseph Adna Hill.[4]

Allocation

In a legislative election under the Huntington–Hill method, after the votes have been tallied, the qualification value would be calculated. This step is necessary because in an election, unlike in a legislative apportionment, not all parties are always guaranteed at least one seat. If the legislature concerned has no exclusion threshold, the qualification value could be a predefined quota, such as the Hare, Droop, or Imperiali quota.

In legislatures which use an exclusion threshold, the qualification value would be equipotent to the threshold, that is:

where

  • total votes is the total valid poll; that is, the number of valid (unspoilt) votes cast in an election.
  • total seats is the total number of seats to be filled in the election.

Every party polling votes equal to or greater than the qualification value would be given an initial number of seats, again varying if whether or not there is a threshold:

In legislatures which do not use an exclusion threshold, the initial number would be 1, but in legislatures which do, the initial number of seats would be:

with all fractional remainders being rounded up.

In legislatures elected under a mixed-member proportional system, the initial number of seats would be further modified by adding the number of single-member district seats won by the party before any allocation.

Determining the qualification value is not necessary when distributing seats in a legislature among states pursuant to census results, where all states are guaranteed a fixed number of seats, either one (as in the US) or a greater number, which may be uniform (as in Brazil) or vary between states (as in Canada).

It can also be skipped if the Huntington-Hill system is used in the nationwide stage of a national remnant system, because the only qualified parties are those which obtained seats at the subnational stage.

After all qualified parties or states received their initial seats, successive quotients are calculated, as in other Highest Averages methods, for each qualified party or state, and seats would be repeatedly allocated to the party or state having the highest quotient until there are no more seats to allocate. The formula of quotients calculated under the Huntington-Hill method is

where:

  • V is the population of the state or the total number of votes that party received, and
  • s is the number of seats that the state or party has been allocated so far.

Example

Even though the Huntington–Hill system was designed to distribute seats in a legislature among states pursuant to census results, it can also be used, when putting parties in the place of states and votes in place of population, for the mathematically equivalent task of distributing seats among parties pursuant to an election results in a party-list proportional representation system. A party-list PR system requires large multi-member districts to function effectively.

In this example, 230,000 voters decide the disposition of 8 seats among 4 parties. Unlike the D'Hondt and Sainte-Laguë systems, which allow the allocation of seats by calculating successive quotients right away, the Huntington–Hill system requires each party or state have at least one seat to avoid a division by zero error. In the U.S. House of Representatives, this is ensured by guaranteeing each state at least one seat; in a single-stage PR election under the Huntington–Hill system, however, the first stage would be to calculate which parties are eligible for an initial seat.

This could be done by excluding any parties which polled less than a predefined quota, and giving every party which polled at least the quota one seat.

Denominator Votes Is the party eligible or disqualified?
Hare Droop Imperiali
Party A 100,000 Eligible Eligible Eligible
Party B 80,000 Eligible Eligible Eligible
Party C 30,000 Eligible Eligible Eligible
Threshold 28,750 25,556 23,000
Party D 20,000 Disqualified Disqualified Disqualified

In this case, the qualified parties stay the same regardless of quota.

Each eligible party is assigned one seat. With all the initial seats assigned, the remaining five seats are distributed by a priority number calculated as follows. Each eligible party's (Parties A, B, and C) total votes is divided by 1.41 (the square root of the product of 1, the number of seats currently assigned, and 2, the number of seats that would next be assigned), then by 2.45, 3.46, 4.47, 5.48, 6.48, 7.48, and 8.49. The 5 highest entries, marked with asterisks, range from 70,711 down to 28,868. For each, the corresponding party gets another seat.

For comparison, the "Proportionate seats" column shows the exact fractional numbers of seats due, calculated in proportion to the number of votes received (For example, 100,000/230,000 × 8 = 3.48). If the "Total Seats" column is less than the "Proportionate seats" column (Parties C[a] and D in this example) the party is under-represented. Conversely, if the "Total Seats" column is greater than the "Proportionate seats" column (Parties A and B in this example) the party is over-represented.[b]

Denominator 1.41 2.45 3.46 4.47 5.48 6.48 7.48 8.49 Initial
seats
Seats
won (*)
Total
Seats
Proportionate
seats[c]
Party A 70,711* 40,825* 28,868* 22,361 18,257 15,430 13,363 11,785 1 3 4 3.5
Party B 56,569* 32,660* 23,094 17,889 14,606 12,344 10,690 9,428 1 2 3 2.8
Party C 21,213 12,247 8,660 6,708 5,477 4,629 4,009 3,536 1 0 1 1.0
Party D Disqualified 0 0.7

If the number of seats was equal in size to the number of votes cast, this method would guarantee that the apportionments would equal the vote shares of each party.

In this example, the results of the apportionment is identical to one under the D'Hondt system. However, as the District magnitude increases, differences emerge: all 120 members of the Knesset, Israel's unicameral legislature, are elected under the D'Hondt method[d]. Had the Huntington–Hill method, rather than the D'Hondt method, been used to apportion seats following the elections to the 20th Knesset, held in 2015, the 120 seats in the 20th Knesset would have been apportioned as follows:

Party Votes Huntington–Hill D'Hondt[d] +/–
(hypothetical) (actual)
Last Priority[e] Next Priority[f] Seats Seats
Likud 985,408 33408 32313 30 30 0
Zionist Union 786,313 33468 32101 24 24 0
Joint List 446,583 35755 33103 13 13 0
Yesh Atid 371,602 35431 32344 11 11 0
Kulanu 315,360 37166 33242 9 10 –1
The Jewish Home 283,910 33459 29927 9 8 +1
Shas 241,613 37282 32287 7 7 0
Yisrael Beiteinu 214,906 39236 33161 6 6 0
United Torah Judaism 210,143 38367 32426 6 6 0
Meretz 165,529 37013 30221 5 5 0
Source: CEC

Compared with the actual apportionment, Kulanu would have lost one seat, while The Jewish Home would have gained one seat.

Footnotes

  1. ^ Party C's proportion is actually 1.04
  2. ^ While this example favors the largest parties (Parties A and B), if a different number of seats were apportioned, other parties would be favored. In short, the largest party is not always favored.
    For example, if there were 12 seats instead of 8, then Party C would be the only over-represented party (since Party D would have qualified) with two full seats while proportionately deserving only 1.6 seats.
  3. ^ This proportionality is based on the total votes. If instead it was based on the qualified votes (i.e., reducing the total 230,000 votes by the disqualified 20,000 votes for Party D), the proportionate seats would be: Party A - 3.8 seats, Party B - 3.0 seats, and Party C - 1.1 seats.
  4. ^ a b The method used for the 20th Knesset was actually a modified D'Hondt, called the Bader-Ofer method. This modification allows for spare vote agreements between parties.[5]
  5. ^ This is each party's last priority number which resulted in a seat being gained by the party. Likud gained the last seat (the 120th seat allocated). Each priority number in this column is greater than any priority number in the Next Priority column.
  6. ^ This is each party's next priority number which would result in a seat being gained by the party. Kulanu would have gained the next seat (if there were 121 seats in the Knesset). Each priority number in this column is less than any priority number in the Last Priority column.

References

  1. ^ "Congressional Apportionment". NationalAtlas.gov. Archived from the original on 2009-02-28. Retrieved 2009-02-14.
  2. ^ Draft House of Lords Reform Bill: report session 2010-12, Vol. 2. Google Books. 23 April 2012. ISBN 9780108475801. Retrieved 6 November 2017.
  3. ^ "Computing Apportionment". United States Census Bureau. Retrieved 2021-04-26.
  4. ^ "The History of Apportionment in America". American Mathematical Society. Retrieved 2009-02-15.
  5. ^ "With Bader-Ofer method, not every ballot counts". The Jerusalem Post. Retrieved 2021-05-04.
This page was last edited on 27 October 2021, at 18:24
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