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If a LED goes open circuit, then, if the voltage is high enough, the current that should have gone through that LED could theoretically find an alternative route through other LEDs.
For example, if LED1 (L1) goes open circuit, then current could still flow from terminal 3 to terminal 2 through L2 and L3. Other possible routes are through L4/L5, L6/L7 and L8/L9.
However, if LED1 goes short circuit, then, any time just one of its terminals is connected to the supply, then both it's terminals are connected to that supply:
If terminals 2 and 3 have opposite polarities, then R2 and R3 will act as a potential divider, halving the voltage at the junction of these resistors. This reduced voltage may prevent other LEDs in the array lighting when they should.
If terminal 2 or terminal 3 is negative, then both the red and brown tracks will be negative at the same time. Therefore, some LEDs connected to these tracks could light up unintentionally when terminals 1, 4, 5 or 6 are positive.
Similarly, if terminal 2 or terminal 3 is positive, then both the red and brown tracks will be positive at the same time. Therefore, some LEDs connected to these tracks could light up unintentionally when terminals 1, 4, 5 or 6 are negative.
Date
Source
Own work
Author
Ron Binstead
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