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File:2D Nonhomogeneous heat equation .gif

From Wikipedia, the free encyclopedia

2D_Nonhomogeneous_heat_equation_.gif(192 × 192 pixels, file size: 924 KB, MIME type: image/gif, looped, 72 frames, 2.9 s)

Summary

Description
Shows an animation of the numerical solution to the 2d heat nonhomogeneous heat equation in a metal slab. Solved with 0 initial and boundary conditions and a source term representing a stove burner.
Date
Source Own work
Author Cale.rankin

Python Source Code

"""
simulates heat equation on rectangle returning a heat map at a number of times
boundary and initial conditions are 0, source represents burner on a stove
This program is based on the script FEniCS tutorial demo program: Diffusion of a Gaussian hill.     
  u'= Laplace(u) + f  in a square domain
  u = u_D = 0            on the boundary
  u = u_0 = 0            at t = 0
  u_D = f = stove burner flame
This program succesfully runs in the fenics docker image, see the book Solving PDEs in Python.
to animate: convert -delay 4 -loop 100 heatequation10*.png heatstovelinn.gif
to crop:convert heatstovelinn.gif -coalesce -repage 0x0 -crop 810x810+95+15 +repage heatstovelin.gif
"""

from fenics import *
import time
import matplotlib.pyplot as plt
from matplotlib import cm

# Create mesh and define function space
nx = ny = 100
mesh = RectangleMesh(Point(-2, -2), Point(2, 2), nx, ny)
V = FunctionSpace(mesh, 'P', 1)

# Define boundary, source, initial
def boundary(x, on_boundary):
    return on_boundary
bc = DirichletBC(V, Constant(0), boundary)
u_0 = interpolate(Constant(0), V)
f = Expression('exp(-sqrt(pow((a*pow(x[0], 2) + a*pow(x[1], 2)-a*1),2)))', degree=2, a=5) #steep guassian centred on the unit sphere

final_time = 0.035
num_pics = 72
for i in range(num_pics):
    T =   final_time*(i+1.0)/(num_pics+1)      #solve time even space
    #T = final_time*1.1**(i-num_pics+1)        #solve time log  space
    num_steps = 30
    dt = T / num_steps # time step size

    # Define variational problem
    u = TrialFunction(V)
    v = TestFunction(V)
    F = u*v*dx + dt*dot(grad(u), grad(v))*dx - (u_0 + dt*f)*v*dx
    a, L = lhs(F), rhs(F)
    
    # Time-stepping
    u = Function(V)
    t = 0
    for n in range(num_steps):
        t += dt              #step
        solve(a == L, u, bc) #solve
        u_0.assign(u)        #update
        
    #plot solution
    plot(u,cmap=cm.hot,vmin=0,vmax=0.07)
    plt.axis('off')
    plt.savefig('heatequation10%s.png'%(i+10),figsize=(8, 8), dpi=220,bbox_inches='tight', pad_inches=0,transparent=True)

Licensing

I, the copyright holder of this work, hereby publish it under the following license:
w:en:Creative Commons
attribution share alike
You are free:
  • to share – to copy, distribute and transmit the work
  • to remix – to adapt the work
Under the following conditions:
  • attribution – You must give appropriate credit, provide a link to the license, and indicate if changes were made. You may do so in any reasonable manner, but not in any way that suggests the licensor endorses you or your use.
  • share alike – If you remix, transform, or build upon the material, you must distribute your contributions under the same or compatible license as the original.

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30 March 2018

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6589c263289e7769b05497d5888848e7cd354d58

945,917 byte

2.88 second

192 pixel

192 pixel

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Date/TimeThumbnailDimensionsUserComment
current09:18, 30 March 2018Thumbnail for version as of 09:18, 30 March 2018192 × 192 (924 KB)Cale.rankinCross-wiki upload from en.wikipedia.org
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