Drazin inverse

In mathematics, the Drazin inverse, named after Michael P. Drazin, is a kind of generalized inverse of a matrix.

Let A be a square matrix. The index of A is the least nonnegative integer k such that rank(A^k+1) = rank(A^k). The Drazin inverse of A is the unique matrix A^D that satisfies

${\displaystyle A^{k+1}A^{\text{D}}=A^{k},\quad A^{\text{D}}AA^{\text{D}}=A^{\text{D}},\quad AA^{\text{D}}=A^{\text{D}}A.}$

It's not a generalized inverse in the classical sense, since ${\displaystyle AA^{\text{D}}A\neq A}$ in general.

• If A is invertible with inverse ${\displaystyle A^{-1}}$, then ${\displaystyle A^{\text{D}}=A^{-1}}$.
• If A is a block diagonal matrix

${\displaystyle A={\begin{bmatrix}B&0\\0&N\end{bmatrix}}}$

where ${\displaystyle B}$ is invertible with inverse ${\displaystyle B^{-1}}$ and ${\displaystyle N}$ is a nilpotent matrix, then

${\displaystyle A^{D}={\begin{bmatrix}B^{-1}&0\\0&0\end{bmatrix}}}$

• Drazin inversion is invariant under conjugation. If ${\displaystyle A^{\text{D}}}$ is the Drazin inverse of ${\displaystyle A}$, then ${\displaystyle PA^{\text{D}}P^{-1}}$ is the Drazin inverse of ${\displaystyle PAP^{-1}}$.
• The Drazin inverse of a matrix of index 0 or 1 is called the group inverse or {1,2,5}-inverse and denoted A^#. The group inverse can be defined, equivalently, by the properties AA^#A = A, A^#AA^# = A^#, and AA^# = A^#A.
• A projection matrix P, defined as a matrix such that P² = P, has index 1 (or 0) and has Drazin inverse P^D = P.
• If A is a nilpotent matrix (for example a shift matrix), then ${\displaystyle A^{\text{D}}=0.}$

The hyper-power sequence is

${\displaystyle A_{i+1}:=A_{i}+A_{i}\left(I-AA_{i}\right);}$ for convergence notice that ${\displaystyle A_{i+j}=A_{i}\sum _{k=0}^{2^{j}-1}\left(I-AA_{i}\right)^{k}.}$

For ${\displaystyle A_{0}:=\alpha A}$ or any regular ${\displaystyle A_{0}}$ with ${\displaystyle A_{0}A=AA_{0}}$ chosen such that ${\displaystyle \left\|A_{0}-A_{0}AA_{0}\right\|<\left\|A_{0}\right\|}$ the sequence tends to its Drazin inverse,

${\displaystyle A_{i}\rightarrow A^{\text{D}}.}$

Jordan normal form and Jordan-Chevalley decomposition

As the definition of the Drazin inverse is invariant under matrix conjugations, writing ${\displaystyle A=PJP^{-1}}$, where J is in Jordan normal form, implies that ${\displaystyle A^{\text{D}}=PJ^{\text{D}}P^{-1}}$. The Drazin inverse is then the operation that maps invertible Jordan blocks to their inverses, and nilpotent Jordan blocks to zero.

More generally, we may define the Drazin inverse over any perfect field, by using the Jordan-Chevalley decomposition ${\displaystyle A=A_{s}+A_{n}}$ where ${\displaystyle A_{s}}$ is semisimple and ${\displaystyle A_{n}}$ is nilpotent and both operators commute. The two terms can be block diagonalized with blocks corresponding to the kernel and cokernel of ${\displaystyle A_{s}}$. The Drazin inverse in the same basis is then defined to be zero on the kernel of ${\displaystyle A_{s}}$, and equal to the inverse of ${\displaystyle A}$ on the cokernel of ${\displaystyle A_{s}}$.

See also

• Constrained generalized inverse
• Inverse element
• Moore–Penrose inverse
• Jordan normal form
• Generalized eigenvector

References

• Drazin, M. P. (1958). "Pseudo-inverses in associative rings and semigroups". The American Mathematical Monthly. 65 (7): 506–514. doi:10.2307/2308576. JSTOR 2308576.
• Zheng, Bing; Bapat, R.B (2004). "Generalized inverse A(2)T,S and a rank equation". Applied Mathematics and Computation. 155 (2): 407. doi:10.1016/S0096-3003(03)00786-0.

External links

• Drazin inverse on Planet Math
• Group inverse on Planet Math

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This page was last edited on 28 July 2023, at 23:43