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2022 Open Harmonie mutuelle – Doubles

From Wikipedia, the free encyclopedia

Jonathan Erlich and Fabrice Martin were the defending champions[1] but chose not to defend their title.

Sander Arends and David Pel won the title after defeating Jonathan Eysseric and Robin Haase 6–3, 6–3 in the final.

Seeds

  1. France Jonathan Eysseric / Netherlands Robin Haase (final)
  2. Netherlands Sander Arends / Netherlands David Pel (champions)
  3. Czech Republic Marek Gengel / Greece Michail Pervolarakis (semifinals)
  4. Austria Neil Oberleitner / Austria David Pichler (first round)

Draw

Key

First round Quarterfinals Semifinals Final
1 France J Eysseric
Netherlands R Haase
6 6
Italy Davide Pozzi
Italy Augusto Virgili
3 3 WC France E Furness
France Q Gueydan
2 3
WC France E Furness
France Quentin Gueydan
6 6 1 France J Eysseric
Netherlands R Haase
77 6
4 Austria N Oberleitner
Austria David Pichler
7 2 [8] France T Arribagé
France H Mayot
64 3
India A Chandrasekar
India VS Prashanth
5 6 [10] India A Chandrasekar
India VS Prashanth
1 6 [6]
France T Arribagé
France H Mayot
4 6 [11] France T Arribagé
France H Mayot
6 3 [10]
WC France Arthur Bouquier
France Martin Breysach
6 3 [9] 1 France J Eysseric
Netherlands R Haase
3 3
Germany H Jebens
Germany Niklas Schell
63 2 2 Netherlands S Arends
Netherlands D Pel
6 6
United Kingdom A Gray
United Kingdom R Peniston
77 6 United Kingdom A Gray
United Kingdom R Peniston
5 6 [8]
Netherlands Mats Hermans
Denmark M Torpegaard
2 4 3 Czech Republic M Gengel
Greece M Pervolarakis
7 2 [10]
3 Czech Republic M Gengel
Greece M Pervolarakis
6 6 3 Czech Republic M Gengel
Greece M Pervolarakis
5 62
Croatia Z Babić
Bulgaria A Donski
6 7 2 Netherlands S Arends
Netherlands D Pel
7 77
France Quentin Folliot
France M Janvier
4 5 Croatia Z Babić
Bulgaria A Donski
65 3
2 Netherlands S Arends
Netherlands D Pel
77 6

References

  1. ^ "Majchrzak Takes First ATP Challenger Title At Open Harmonie Mutuelle". March 31, 2019.

External links

This page was last edited on 24 July 2023, at 17:43
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