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2019 Bangkok Challenger II – Doubles

From Wikipedia, the free encyclopedia

James Cerretani and Joe Salisbury were the defending champions but chose not to defend their title.

Li Zhe and Gonçalo Oliveira won the title after defeating Enrique López Pérez and Hiroki Moriya 6–2, 6–1 in the final.

Seeds

  1. China Gong Maoxin / China Zhang Ze (semifinals, withdrew)
  2. Australia Max Purcell / Australia Matt Reid (semifinals)
  3. China Li Zhe / Portugal Gonçalo Oliveira (champions)
  4. India Sriram Balaji / India Arjun Kadhe (first round)

Draw

Key

First round Quarterfinals Semifinals Final
1 China M Gong
China Ze Zhang
77 6
ITF Spain D Pérez Sanz
Spain O Roca Batalla
64 0 1 China M Gong
China Ze Zhang
w/o
WC Thailand Vorachon Rakpuangchon
Thailand Tanakorn Srirat
3 2 Russia I Gakhov
Italy G Mager
Russia I Gakhov
Italy G Mager
6 6 1 China M Gong
China Ze Zhang
4 India S Balaji
India A Kadhe
7 4 [9] Spain E López Pérez
Japan H Moriya
w/o
Spain E López Pérez
Japan H Moriya
5 6 [11] Spain E López Pérez
Japan H Moriya
6 6
Thailand Sa Ratiwatana
Thailand So Ratiwatana
6 6 Thailand Sa Ratiwatana
Thailand So Ratiwatana
3 2
WC Thailand Chotiwat Naen-Udorn
Thailand Patthavut Saimongkol
1 0 Spain E López Pérez
Japan H Moriya
2 1
ITF Philippines F Alcantara
Portugal B Saraiva
77 77 3 China Z Li
Portugal G Oliveira
6 6
Israel J Erlich
India S Myneni
64 64 ITF Philippines F Alcantara
Portugal B Saraiva
5 3
Kazakhstan T Khabibulin
Chinese Taipei T-h Yang
3 2 3 China Z Li
Portugal G Oliveira
7 6
3 China Z Li
Portugal G Oliveira
6 6 3 China Z Li
Portugal G Oliveira
77 6
Philippines R Gonzales
United States A Lawson
6 6 2 Australia M Purcell
Australia M Reid
62 4
WC Thailand P Isaro
Thailand Chanchai Sookton-Eng
1 2 Philippines R Gonzales
United States A Lawson
4 2
Finland H Heliövaara
Japan T Matsui
6 3 [4] 2 Australia M Purcell
Australia M Reid
6 6
2 Australia M Purcell
Australia M Reid
3 6 [10]

References

This page was last edited on 5 December 2023, at 18:15
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