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2019 ATP Finals – Doubles

From Wikipedia, the free encyclopedia

Doubles
2019 ATP Finals
Final
ChampionsFrance Pierre-Hugues Herbert
France Nicolas Mahut
Runners-upSouth Africa Raven Klaasen
New Zealand Michael Venus
Score6–3, 6–4
Events
Singles Doubles
← 2018 · ATP Finals · 2020 →

Pierre-Hugues Herbert and Nicolas Mahut defeated Raven Klaasen and Michael Venus in the final, 6–3, 6–4 to win the doubles tennis title at the 2019 ATP Finals.

Mike Bryan and Jack Sock were the reigning champions, but Sock did not qualify this year. Bryan qualified alongside his brother Bob, but they withdrew before the tournament.[1]

Seeds

Alternates

Draw

Key

Finals

Semifinals Final
          
7 France Pierre-Hugues Herbert
France Nicolas Mahut
6 77
2 Poland Łukasz Kubot
Brazil Marcelo Melo
3 64
7 France Pierre-Hugues Herbert
France Nicolas Mahut
6 6
5 South Africa Raven Klaasen
New Zealand Michael Venus
3 4
5 South Africa Raven Klaasen
New Zealand Michael Venus
65 712 [10]
1 Colombia Juan Sebastián Cabal
Colombia Robert Farah
77 610 [6]

Group Max Mirnyi

Colombia Cabal
Colombia Farah
Germany Krawietz
Germany Mies
Netherlands Rojer
Romania Tecău
France Herbert
France Mahut
RR W–L Set W–L Game W–L Standings
1 Colombia Juan Sebastián Cabal
Colombia Robert Farah
7–6(9–7), 6–2 2–6, 7–5, [8–10] 3–6, 5–7 1–2 3–4 (43%) 30–33 (48%) 2
3 Germany Kevin Krawietz
Germany Andreas Mies
6–7(7–9), 2–6 7–6(7–3), 4–6, [10–6] 5–7, 6–7(3–7) 1–2 2–5 (29%) 31–39 (44%) 4
6 Netherlands Jean-Julien Rojer
Romania Horia Tecău
6–2, 5–7, [10–8] 6–7(3–7), 6–4, [6–10] 3–6, 6–7(4–7) 1–2 3–5 (38%) 33–34 (49%) 3
7 France Pierre-Hugues Herbert
France Nicolas Mahut
6–3, 7–5 7–5, 7–6(7–3) 6–3, 7–6(7–4) 3–0 6–0 (100%) 40–28 (59%) 1

Group Jonas Björkman

Poland Kubot
Brazil Melo
United States Ram
United Kingdom Salisbury
South Africa Klaasen
New Zealand Venus
Croatia Dodig
Slovakia Polášek
RR W–L Set W–L Game W–L Standings
2 Poland Łukasz Kubot
Brazil Marcelo Melo
6–7(5–7), 6−4, [10–7] 3–6, 4–6 4–6, 6–4, [10–5] 2–1 4–4 (50%) 31–33 (48%) 2
4 United States Rajeev Ram
United Kingdom Joe Salisbury
7–6(7–5), 4–6, [7–10] 3–6, 4–6 3–6, 6–3, [10–6] 1–2 3–5 (38%) 28–34 (45%) 3
5 South Africa Raven Klaasen
New Zealand Michael Venus
6–3, 6–4 6–3, 6–4 6–7(4–7), 4–6 2–1 4–2 (67%) 34–27 (56%) 1
8 Croatia Ivan Dodig
Slovakia Filip Polášek
6–4, 4–6, [5–10] 6–3, 3–6, [6–10] 7–6(7–4), 6–4 1–2 4–4 (50%) 32–31 (51%) 4

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head results; 4. in three-players-ties, percentage of sets won, then head-to-head result (if two players tied in percentage of sets won and third one is "different") or percentage of games won if all three players have same percentage of sets won, then head-to-head results; 5. ATP rankings.[2]

References

  1. ^ "Doubles Groups Announced For 2019 Nitto ATP Finals". ATP Tour. 5 November 2019.
  2. ^ "Semi-final Qualifying Procedure". Nitto ATP Finals.

External links

This page was last edited on 5 July 2022, at 22:08
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