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2018 Marburg Open – Doubles

From Wikipedia, the free encyclopedia

Máximo González and Fabrício Neis were the defending champions but only Neis chose to defend his title, partnering David Vega Hernández. Neis successfully defended his title.

Neis and Vega Hernández won the title after defeating Henri Laaksonen and Luca Margaroli 4–6, 6–4, [10–8] in the final.

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Transcription

Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 Brazil F Neis
Spain D Vega Hernández
4 6 [11]
WC Germany B Hassan
Germany Constantin Schmitz
6 4 [9] 1 Brazil F Neis
Spain D Vega Hernández
6 5 [10]
South Africa L Harris
South Africa R Roelofse
6 3 [10] South Africa L Harris
South Africa R Roelofse
3 7 [7]
Germany M Moraing
Germany O Otte
3 6 [7] 1 Brazil F Neis
Spain D Vega Hernández
6 77
3 Germany D Brown
Australia R Junaid
1 4 Slovakia A Martin
Portugal G Oliveira
3 65
Kazakhstan T Khabibulin
Ukraine V Manafov
6 6 Kazakhstan T Khabibulin
Ukraine V Manafov
1 5
Poland G Panfil
Russia A Vatutin
3 3 Slovakia A Martin
Portugal G Oliveira
6 7
Slovakia A Martin
Portugal G Oliveira
6 6 1 Brazil F Neis
Spain D Vega Hernández
4 6 [10]
Australia M Polmans
Croatia N Serdarušić
5 4 Switzerland H Laaksonen
Switzerland L Margaroli
6 4 [8]
WC France E Benchetrit
Germany R Molleker
7 6 WC France E Benchetrit
Germany R Molleker
Peru S Galdós
Argentina JI Londero
2 3 4 Mexico H Hach Verdugo
Sweden A Siljeström
w/o
4 Mexico H Hach Verdugo
Sweden A Siljeström
6 6 4 Mexico H Hach Verdugo
Sweden A Siljeström
6 5 [9]
WC Germany R Kern
Germany J Lenz
7 2 [10] Switzerland H Laaksonen
Switzerland L Margaroli
3 7 [11]
Poland T Bednarek
Romania F Mergea
5 6 [5] WC Germany R Kern
Germany J Lenz
63 2
Switzerland H Laaksonen
Switzerland L Margaroli
66 6 [10] Switzerland H Laaksonen
Switzerland L Margaroli
77 6
2 United States N Pasha
United States H Reese
78 3 [6]

References

This page was last edited on 21 June 2022, at 13:20
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