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2018 Glasgow Trophy – Doubles

From Wikipedia, the free encyclopedia

Doubles

2018 Glasgow Trophy

Final

Champions

Gerard Granollers

Guillermo Olaso

Runners-up

Score

6–1, 7–5

Events

Glasgow Trophy

· 2019 →

This was the first edition of the tournament.

Gerard Granollers and Guillermo Olaso won the title after defeating Scott Clayton and Jonny O'Mara 6–1, 7–5 in the final.

Seeds

Scott Clayton / Jonny O'Mara (final)
Roberto Ortega Olmedo / Mario Vilella Martínez (first round)
Alessandro Bega / Lucas Miedler (quarterfinals)
Harri Heliövaara / Evgeny Karlovskiy (semifinals)

Draw

Key

	First round							Quarterfinals							Semifinals							Final

	1	S Clayton J O'Mara	6⁷	6	[10]
		H Moriya K Uchida	7⁹	2	[5]			1	S Clayton J O'Mara	6	6
	PR	L Glasspool J Ward	6⁵	6	[6]			PR	JP Fruttero I Sijsling	4	2
	PR	JP Fruttero I Sijsling	7⁷	2	[10]										1	S Clayton J O'Mara	6	6
	3	A Bega L Miedler	3	7⁹	[10]											D Guez Y Mertens	3	2
	WC	J Fearnley C Thomson	6	6⁷	[6]			3	A Bega L Miedler	6⁵	6	[5]
		Marek Jaloviec B Zapata Miralles	1	1					D Guez Y Mertens	7⁷	1	[10]
		D Guez Y Mertens	6	6																		1	S Clayton J O'Mara	1	5
		N Milojević L Vanni	3	6	[10]																		G Granollers G Olaso	6	7
	Alt	D Brands R Kern	6	3	[4]				N Milojević L Vanni	3	6²
	WC	Reuben Henry Scott MacAulay	2	2				4	H Heliövaara E Karlovskiy	6	7⁷
	4	H Heliövaara E Karlovskiy	6	6											4	H Heliövaara E Karlovskiy	3	4
		JC Aragone Jared Hiltzik	4	6	[5]											G Granollers G Olaso	6	6
	WC	S Duncan Kieran MacArty	6	2	[10]			WC	S Duncan K MacArty	5	4
		G Granollers G Olaso	7	6					G Granollers G Olaso	7	6
	2	R Ortega Olmedo M Vilella Martínez	5	3

References

Main Draw

This page was last edited on 2 December 2023, at 16:43

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