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2015 San Benedetto Tennis Cup – Doubles

From Wikipedia, the free encyclopedia

Daniele Giorgini and Potito Starace are the defending champions, but they decided not to participate this year.

Dino Marcan and Antonio Šančić won the title, defeating César Ramírez and Miguel Ángel Reyes-Varela in the final 6–3, 6–710–12, [12–10].

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  • ATP San Benedetto. Gianluigi Quinzi Wimbledon junior champion press conference

Transcription

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Mexico C Ramírez
Mexico MA Reyes-Varela
6 6
  Bosnia and Herzegovina D Džumhur
Netherlands S Groen
4 0 1 Mexico C Ramírez
Mexico MA Reyes-Varela
6 6
  Croatia T Androić
Italy Matteo Marfia
3 2 Italy M Cecchinato
Italy F Gaio
4 2
  Italy M Cecchinato
Italy F Gaio
6 6 1 Mexico C Ramírez
Mexico MA Reyes-Varela
77 6
3 Italy F Cipolla
Italy A Motti
7 6 3 Italy F Cipolla
Italy A Motti
62 3
  Egypt M Safwat
India D Sharan
5 2 3 Italy F Cipolla
Italy A Motti
3 6 [10]
WC United States C Altamirano
United States T-S Kwiatkowski
6 6 WC United States C Altamirano
United States T-S Kwiatkowski
6 2 [4]
  Romania Alexandru-Daniel Carpen
Italy R Ghedin
2 2 1 Mexico C Ramírez
Mexico MA Reyes-Varela
3 712 [10]
WC Italy S Caruso
Italy G Naso
6 6 2 Croatia D Marcan
Croatia A Šančić
6 610 [12]
  Italy R Marcora
Italy M Viola
2 2 WC Italy S Caruso
Italy G Naso
2 4
  Italy A Giannessi
Spain A Ramos-Viñolas
2 4 4 United States J Cerretani
Romania C Pavăl
6 6
4 United States J Cerretani
Romania C Pavăl
6 6 4 United States J Cerretani
Romania C Pavăl
6 3 [4]
  Italy Enrico Becuzzi
Italy P Lorenzi
0 0 2 Croatia D Marcan
Croatia A Šančić
4 6 [10]
Croatia N Mektić
Croatia A Veić
6 6 Croatia N Mektić
Croatia A Veić
4 5
WC Italy Edoardo Eremin
Italy S Napolitano
4 69 2 Croatia D Marcan
Croatia A Šančić
6 7
2 Croatia D Marcan
Croatia A Šančić
6 711

References

This page was last edited on 27 February 2022, at 23:20
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