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2015 Open Harmonie mutuelle – Doubles

From Wikipedia, the free encyclopedia

Dominik Meffert and Tim Pütz were the defending champions, but decided not to compete.

Grégoire Burquier and Alexandre Sidorenko won the title, defeating Andriej Kapaś and Yasutaka Uchiyama in the final, 6–3, 6–4.

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Netherlands W Koolhof
Netherlands M Middelkoop
w/o
United Kingdom D Cox
United Kingdom M Willis
1 Netherlands W Koolhof
Netherlands M Middelkoop
6 4 [9]
  Belgium J Cagnina
Belgium G Gigounon
6 65 [10] Belgium J Cagnina
Belgium G Gigounon
1 6 [11]
Republic of Ireland J Cluskey
Republic of Ireland D O'Hare
2 77 2   Belgium J Cagnina
Belgium G Gigounon
3 3
3 Germany A Beck
United Kingdom K Skupski
3 6 [7] WC France G Burquier
France A Sidorenko
6 6
WC France G Barrère
France M Gicquel
6 1 [10] WC France G Barrère
France M Gicquel
64 4
  Czech Republic J Hernych
Czech Republic J Mertl
6 62 [10] WC France G Burquier
FranceA Sidorenko
77 6
WC France G Burquier
France A Sidorenko
3 77 [12] WC France G Burquier
France A Sidorenko
6 6
Alt Croatia T Androić
Croatia N Mektić
w/o 4 Poland A Kapaś
Japan Y Uchiyama
3 4
Belgium Y Mertens
Netherlands I Sijsling
Alt Croatia T Androić
Croatia N Mektić
6 3 [8]
Belarus U Ignatik
Czech Republic M Michalička
5 2 4 Poland A Kapaś
Japan Y Uchiyama
1 6 [10]
4 Poland A Kapaś
Japan Y Uchiyama
6 7 4 Poland A Kapaś
Japan Y Uchiyama
6 7
Romania P Grigoriu
Romania C Pavăl
6 2 [10] 2 Philippines R Gonzales
United Kingdom D Walsh
2 5
Netherlands J Huta Galung
Japan Y Sugita
2 6 [5]   Romania P Grigoriu
Romania C Pavăl
3 4
WC France R Boutillier
France Q Halys
2 66 2 Philippines R Gonzales
United Kingdom D Walsh
6 6
2 Philippines R Gonzales
United Kingdom D Walsh
6 78

References

This page was last edited on 27 February 2022, at 23:15
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