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2014 Open de Nice Côte d'Azur – Doubles

From Wikipedia, the free encyclopedia

Johan Brunström and Raven Klaasen were the defending champions, but Brunström chose not to participate this year. Klaasen played alongside Eric Butorac, but lost in the first round to Andre Begemann and Robin Haase.

Martin Kližan and Philipp Oswald won the title, defeating Rohan Bopanna and Aisam-ul-Haq Qureshi in the final, 6–2, 6–0.

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Transcription

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 India R Bopanna
Pakistan A-u-H Qureshi
6 6
Australia M Ebden
Russia D Tursunov
4 4 1 India R Bopanna
Pakistan A-u-H Qureshi
5 77 [10]
Italy D Bracciali
Austria O Marach
6 63 [10] Italy D Bracciali
Austria O Marach
7 65 [5]
France G Monfils
France B Paire
4 77 [2] 1 India R Bopanna
Pakistan A-u-H Qureshi
4 77 [10]
3 France J Benneteau
France É Roger-Vasselin
77 6 3 France J Benneteau
France É Roger-Vasselin
6 62 [8]
Australia R Junaid
New Zealand M Venus
65 2 3 France J Benneteau
France É Roger-Vasselin
6 5 [10]
Croatia M Pavić
Brazil A Sá
1 6 [10] Croatia M Pavić
Brazil A Sá
4 7 [5]
Germany P Marx
Romania F Mergea
6 3 [2] 1 India R Bopanna
Pakistan A-u-H Qureshi
2 0
Slovakia M Kližan
Austria P Oswald
6 6 Slovakia M Kližan
Austria P Oswald
6 6
WC Chinese Taipei H-h Lee
Chinese Taipei C-f Wang
3 4 Slovakia M Kližan
Austria P Oswald
6 6
Germany A Begemann
Netherlands R Haase
78 6 Germany A Begemann
Netherlands R Haase
3 3
4 United States E Butorac
South Africa R Klaasen
66 4 Slovakia M Kližan
Austria P Oswald
3 6 [10]
Argentina C Berlocq
Argentina L Mayer
6 6 United Kingdom K Skupski
United Kingdom N Skupski
6 3 [2]
WC India S Devvarman
India P Raja
2 4 Argentina C Berlocq
Argentina L Mayer
1 62
United Kingdom K Skupski
United Kingdom N Skupski
7 5 [10] United Kingdom K Skupski
United Kingdom N Skupski
6 77
2 Netherlands J-J Rojer
Romania H Tecău
5 7 [6]

External links

This page was last edited on 28 November 2022, at 22:31
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