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2013 Hall of Fame Tennis Championships – Doubles

From Wikipedia, the free encyclopedia

Santiago González and Scott Lipsky were the defending champions, but lost in the first round to Denis Kudla and Michael Russell.
Nicolas Mahut and Édouard Roger-Vasselin won the title, defeating Tim Smyczek and Rhyne Williams, 6–7(4–7), 6–2, [10–5].

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Transcription

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Mexico S González
United States S Lipsky
6 66 4
United States D Kudla
United States M Russell
4 78 [10] United States D Kudla
United States M Russell
2 3
United States T Smyczek
United States R Williams
6 6 United States T Smyczek
United States R Williams
6 6
Australia M Matosevic
Germany F Moser
3 2 United States T Smyczek
United States R Williams
77 65 [10]
3 United States J Blake
United States R Ram
4 77 [6] Croatia I Karlović
India D Sharan
62 77 [8]
Canada A Shamasdin
Australia J-P Smith
6 63 [10] Canada A Shamasdin
Australia J-P Smith
4 6 [17]
Ukraine I Marchenko
Ukraine D Molchanov
6 61 [9] Croatia I Karlović
India D Sharan
6 4 [19]
Croatia I Karlović
India D Sharan
4 77 [11] United States T Smyczek
United States R Williams
77 2 [5]
Australia M Ebden
Netherlands I Sijsling
6 6 2 France N Mahut
France É Roger-Vasselin
64 6 [10]
Alt Venezuela E Gil
United States K Kolev
2 1 Australia M Ebden
Netherlands I Sijsling
3 2
Australia C Guccione
Australia L Hewitt
6 3 [5] 4 Brazil M Demoliner
Brazil A Sá
6 6
4 Brazil M Demoliner
Brazil A Sá
4 6 [10] 4 Brazil M Demoliner
Brazil A Sá
4 64
Belgium R Bemelmans
Poland M Przysiężny
6 3 [5] 2 France N Mahut
France É Roger-Vasselin
6 77
WC India P Amritraj
United States S Querrey
4 6 [10] WC India P Amritraj
United States S Querrey
United States J Cerretani
France K de Schepper
3 4 2 France N Mahut
France É Roger-Vasselin
w/o
2 France N Mahut
France É Roger-Vasselin
6 6

References

This page was last edited on 27 February 2022, at 22:43
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