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2006 Hypo Group Tennis International – Doubles

From Wikipedia, the free encyclopedia

Lucas Arnold and Paul Hanley were the defending champions, but did not participate together this year. Arnold partnered Martín García, losing in the semifinals. Hanley partnered Jim Thomas, winning the title.

Hanley and Thomas defeated Oliver Marach and Cyril Suk 6–3, 4–6, [10–5] in the final.

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Australia P Hanley
United States J Thomas
2 6 [10]
  Czech Republic P Pála
Czech Republic D Škoch
6 3 [8] 1 Australia P Hanley
United States J Thomas
6 6  
  Czech Republic F Čermák
Czech Republic T Zíb
65 6 [12]   Czech Republic T Cibulec
Czech Republic J Novák
1 2  
  Czech Republic T Cibulec
Czech Republic J Novák
77 3 [14] 1 Australia P Hanley
United States J Thomas
6 6  
3 Czech Republic L Dlouhý
Czech Republic P Vízner
6 7     Argentina L Arnold
Argentina M García
3 2  
WC Austria A Peya
Netherlands R Wassen
2 5   3 Czech Republic L Dlouhý
Czech Republic P Vízner
     
  Argentina L Arnold
Argentina M García
77 6     Argentina L Arnold
Argentina M García
w/o    
  South Africa J Coetzee
United States T Parrott
63 3   1 Australia P Hanley
United States J Thomas
6 4 [10]
  United States V Spadea
Russia D Tursunov
6 62 [10]   Austria O Marach
Czech Republic C Suk
3 6 [5]
  Slovakia D Hrbatý
Czech Republic J Levinský
2 77 [5]   United States V Spadea
Russia D Tursunov
4 6 [3]
  Austria O Marach
Czech Republic C Suk
5 6 [12]   Austria O Marach
Czech Republic C Suk
6 2 [10]
4 South Africa C Haggard
Sweden R Lindstedt
7 4 [10]   Austria O Marach
Czech Republic C Suk
6 5 [10]
Alt Argentina C Berlocq
Brazil M Daniel
5 3   2 India M Bhupathi
Austria J Knowle
1 7 [5]
  Argentina JI Chela
Peru L Horna
7 6     Argentina JI Chela
Peru L Horna
     
  Switzerland Y Allegro
Australia J Kerr
5 6 [7] 2 India M Bhupathi
Austria J Knowle
w/o    
2 India M Bhupathi
Austria J Knowle
7 4 [10]

External links

This page was last edited on 8 November 2022, at 07:13
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