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2005 If Stockholm Open – Doubles

From Wikipedia, the free encyclopedia

Feliciano López and Fernando Verdasco were the defending champions, but did not participate this year.

Wayne Arthurs and Paul Hanley won the title, defeating Leander Paes and Nenad Zimonjić 5–3, 5–3 in the final.

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Transcription

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 India L Paes
Serbia and Montenegro N Zimonjić
1 5 5
  Argentina JI Chela
Chile N Massú
5 2 2 1 India L Paes
Serbia and Montenegro N Zimonjić
510 2 5
  Argentina J Acasuso
Spain D Ferrer
3 5 1   Zimbabwe W Black
South Africa C Haggard
48 5 2
  Zimbabwe W Black
South Africa C Haggard
5 3 5 1 India L Paes
Serbia and Montenegro N Zimonjić
w/o    
3 Sweden S Aspelin
Australia T Perry
5 59   3 Sweden S Aspelin
Australia T Perry
     
  Belgium C Rochus
Belgium O Rochus
1 47   3 Sweden S Aspelin
Australia T Perry
5 2 5
  France P-H Mathieu
France G Monfils
1 0   WC Sweden E Eleskovic
Sweden J Landsberg
3 5 1
WC Sweden E Eleskovic
Sweden J Landsberg
5 5   1 India L Paes
Serbia and Montenegro N Zimonjić
3 3  
  Germany M Kohlmann
Germany A Waske
3 43   2 Australia W Arthurs
Australia P Hanley
5 5  
  Argentina M García
Argentina S Prieto
5 57     Argentina M García
Argentina S Prieto
3 2  
  Sweden J Björkman
Sweden T Johansson
5 5     Sweden J Björkman
Sweden T Johansson
5 5  
4 Australia S Huss
South Africa W Moodie
3 3     Sweden J Björkman
Sweden T Johansson
514 42 3
  Switzerland Y Allegro
United States G Oliver
3 43   2 Australia W Arthurs
Australia P Hanley
412 57 5
WC Slovakia K Beck
Sweden R Lindstedt
5 57   WC Slovakia K Beck
Sweden R Lindstedt
3 57 1
  Italy D Sanguinetti
United States V Spadea
2 47   2 Australia W Arthurs
Australia P Hanley
5 43 5
2 Australia W Arthurs
Australia P Hanley
5 59  

References

This page was last edited on 8 November 2022, at 17:30
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