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1998 United States Senate election in Iowa

From Wikipedia, the free encyclopedia

1998 United States Senate election in Iowa

← 1992 November 3, 1998 2004 →
 
Chuck Grassley official photo.jpg
David Osterberg.jpg
Nominee Chuck Grassley David Osterberg
Party Republican Democratic
Popular vote 648,480 289,049
Percentage 68.41% 30.49%

Iowa Senate Election Results by County, 1998.svg
County Results
Grassley:      50-60%      60-70%      70-80%      80-90%      90-100%

U.S. Senator before election

Chuck Grassley
Republican

Elected U.S. Senator

Chuck Grassley
Republican

The 1998 United States Senate election in Iowa was held November 3, 1998. Incumbent Republican United States Senator Chuck Grassley sought re-election to a fourth term in the United States Senate, running against former State Representative David Osterberg, who won the Democratic nomination unopposed. Grassley had not faced a competitive election since 1980; this year proved no different, and Grassley defeated Osterberg in a landslide.

Democratic primary

Candidates

Results

Democratic primary results[1]
Party Candidate Votes %
Democratic David Osterberg 86,064 99.45%
Democratic Write-ins 476 0.55%
Total votes 86,540 100.00%

Republican primary

Candidates

Results

Republican primary results[1]
Party Candidate Votes %
Republican Chuck Grassley (Incumbent) 149,943 99.72%
Republican Write-ins 419 0.28%
Total votes 150,362 100.00%

General election

Results

United States Senate election in Iowa, 1998[2]
Party Candidate Votes % ±
Republican Chuck Grassley (Incumbent) 648,480 68.41% -1.20%
Democratic David Osterberg 289,049 30.49% +3.29%
Natural Law Susan Marcus 7,561 0.80% -0.47%
Socialist Workers Margaret Trowe 2,542 0.27% +0.16%
Write-ins 275 0.03%
Majority 359,431 37.92% -4.50%
Turnout 947,907
Republican hold Swing

See also

References

This page was last edited on 3 February 2019, at 06:03
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