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1996 United States presidential election in Iowa

From Wikipedia, the free encyclopedia

United States presidential election in Iowa, 1996

← 1992 November 5, 1996 2000 →
Bill Clinton.jpg
Bob Dole, PCCWW photo portrait.JPG
Nominee Bill Clinton Bob Dole Ross Perot
Party Democratic Republican Reform
Home state Arkansas Kansas Texas
Running mate Al Gore Jack Kemp James Campbell
Electoral vote 7 0 0
Popular vote 620,258 492,644 105,159
Percentage 50.26% 39.92% 8.52%

Iowa Presidential Election Results by County, 1996.svg
County Results

President before election

Bill Clinton

Elected President

Bill Clinton

The 1996 United States presidential election in Iowa took place on November 7, 1996, as part of the 1996 United States presidential election. Voters chose 7 representatives, or electors to the Electoral College, who voted for president and vice president.

Iowa was won by Democratic incumbent President Bill Clinton over Republican Senator Bob Dole of Kansas, with Clinton winning 50.26% of the vote to Dole's 39.92%, a margin of 10.34%. The Reform Party candidate, billionaire businessman Ross Perot, finished in third, with 8.52% of the popular vote.[1]

Iowa is one of thirteen states where on the election ballot, James Campbell of California, Perot's former boss at IBM, was listed as a stand-in Vice-Presidential candidate.[1][2]

As of the 2016 presidential election, this is the last time Iowa was decided by a double-digit margin. It is also the last time that Monona County, Appanoose County, Decatur County, Henry County, Butler County, Clay County, Dickinson County, Guthrie County, Keokuk County, Madison County, Lucas County, Wright County, Pocahontas County, Taylor County, Van Buren County, Wayne County, Dallas County, Washington County, Cherokee County, Hancock County, Calhoun County, Davis County, Monroe County, Adair County, and Ringgold County voted Democratic.


United States presidential election in Iowa, 1996
Party Candidate Running mate Votes Percentage Electoral votes
Democratic Bill Clinton (incumbent) Al Gore 620,258 50.26% 7
Republican Robert Dole Jack Kemp 492,644 39.92% 0
Reform Ross Perot James Campbell 105,159 8.52% 0
Green Ralph Nader Anne Goeke[1][3] 6,550 0.53% 0
Natural Law Dr. John Hagelin Dr. V. Tompkins 3,349 0.27% 0
Libertarian IA Harry Browne Jo Jorgensen 2,315 0.19% 0
Taxpayer Howard Phillips Albion W. Knight Jr.[1][4] 2,229 0.18% 0
No party Write-in 1,240 0.10% 0
Socialist Workers James Harris Laura Garza 331 0.03% 0
Totals 1,234,075 100.0% 7
Voter Turnout (Voting age/Registered) 58%/69%


  1. ^ a b c d Dave Leip's Atlas of United States Presidential Election Results - 1996 Iowa Results
  2. ^ "Perot Names Stand-in Veep Candidate". Archived from the original on 2008-05-17. Retrieved 2012-01-31.
  3. ^ Iowa is one of the states where Ralph Nader's running mate (Winona LaDuke) was replaced on the ballot by Anne Goeke.
  4. ^ "President Elect - 1996". Archived from the original on 2012-01-14. Retrieved 2012-01-19.

See also

This page was last edited on 9 September 2019, at 10:21
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