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1990 Wyoming gubernatorial election

From Wikipedia, the free encyclopedia

1990 Wyoming gubernatorial election

← 1986 November 6, 1990 (1990-11-06) 1994 →
Turnout71.99% Registered Increase 2.00%
35.30% of Total Population Increase 0.22%
 
WY Governor Mike Sullivan WSA OH-2104.jpg
No image.svg
Nominee Mike Sullivan Mary Mead
Party Democratic Republican
Popular vote 104,638 55,471
Percentage 65.4% 34.6%

Wyoming Gubernatorial Election Results by County, 1990.svg
County Results

Sullivan:      50–60%      60–70%      70–80%

Mead:      50-60%

Governor before election

Mike Sullivan
Democratic

Elected Governor

Mike Sullivan
Democratic

The Wyoming gubernatorial election of 1990 took place on November 6, 1990. Incumbent Democrat Mike Sullivan ran for re-election as Governor of Wyoming. Sullivan defeated Republican businesswoman Mary Mead.

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Transcription

Contents

Democratic primary

Candidates

Democratic primary results[1]
Party Candidate Votes %
Democratic Mike Sullivan (inc.) 38,447 88.44
Democratic Ron Clingman 5,026 11.56
Total votes 43,473 100

Republican primary

Candidates

Republican primary results[2]
Party Candidate Votes %
Republican Mary Mead 51,560 67.25
Republican Nyla Murphy 24,916 32.75
Total votes 76,476 100

Results

Wyoming gubernatorial election, 1990[3]
Party Candidate Votes % ±
Democratic Mike Sullivan (inc.) 104,638 65.35
Republican Mary Mead 55,471 34.65
Total votes 160,109 100

References

  1. ^ "WY Governor - D Primary". Our Campaigns. Retrieved December 11, 2017.
  2. ^ "WY Governor - R Primary". Our Campaigns. Retrieved December 11, 2017.
  3. ^ "1990 Gubernatorial General Election Results - Wyoming". U.S Election Atlas. Retrieved 30 April 2017.


This page was last edited on 22 January 2020, at 05:03
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