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1990 Big Eight Conference men's basketball tournament

From Wikipedia, the free encyclopedia

1990 Big Eight Conference men's basketball tournament
ClassificationDivision I
Season1989–90
Teams8
Finals siteKemper Arena
Kansas City, MO
ChampionsOklahoma (4th title)
Winning coachBilly Tubbs (3rd title)
MVPShaun Vandiver (Colorado)
TelevisionRaycom Sports (Quarterfinals, Semi-Finals and Championship)
ABC(Championship game)
← 1989
1991 →
1989–90 Big Eight Conference men's basketball standings
Conf Overall
Team W   L   PCT W   L   PCT
No. 11 Missouri 12 2   .857 26 6   .813
No. 1 Oklahoma 11 3   .786 27 5   .844
No. 5 Kansas 11 3   .786 30 5   .857
Kansas State 7 7   .500 17 15   .531
Oklahoma State 6 8   .429 17 14   .548
Iowa State 4 10   .286 10 18   .357
Nebraska 3 11   .214 10 18   .357
Colorado 2 12   .143 12 18   .400
1990 Big Eight tournament winner
As of March 3, 2012
Rankings from AP poll

The 1990 Big Eight men's basketball tournament was held March 9–11 at Kemper Arena in Kansas City, Missouri.[1]

Second-seeded Oklahoma defeated #8 seed Colorado in the championship game, 92–80, to earn the conference's automatic bid to the 1990 NCAA tournament.

Bracket

Quarterfinals
Friday, March 9
Semifinals
Saturday, March 10
Championship
Sunday, March 11
         
1 #6 Missouri 88
8 Colorado 92
8 Colorado 82
5 Oklahoma State 72
4 Kansas State 78
5 Oklahoma State 82
8 Colorado 80
2 #1 Oklahoma 92
3 #2 Kansas 118
6 Iowa State 75
3 #2 Kansas 77
2 #1 Oklahoma 95
7 Nebraska 65
2 #1 Oklahoma 78

References

  1. ^ "1989-90 Big 8 Conference Season Summary". sports-reference.com. Sports Reference. Retrieved March 31, 2019.
This page was last edited on 19 August 2023, at 06:21
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