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1989 Big Eight Conference men's basketball tournament

From Wikipedia, the free encyclopedia

1989 Big Eight Conference men's basketball tournament
ClassificationDivision I
Season1988–89
Teams8
Finals siteKemper Arena
Kansas City, MO
ChampionsMissouri (4th title)
Winning coachNorm Stewart (4th title)
MVPDoug Smith (Missouri)
TelevisionRaycom Sports (Quarterfinals, Semi-Finals and Championship)
ABC (Championship game)
← 1988
1990 →
1988–89 Big Eight Conference men's basketball standings
Conf Overall
Team W   L   PCT W   L   PCT
No. 4 Oklahoma 12 2   .857 30 6   .833
No. 6 Missouri 10 4   .714 29 8   .784
Kansas State 8 6   .571 19 11   .633
Oklahoma State 7 7   .500 17 13   .567
Iowa State 7 7   .500 17 12   .586
Kansas 6 8   .429 19 12   .613
Nebraska 4 10   .286 17 16   .515
Colorado 2 12   .143 7 21   .250
1989 Big Eight tournament winner
As of March 3, 2012
Rankings from AP poll


The 1989 Big Eight men's basketball tournament was held March 10–12 at Kemper Arena in Kansas City, Missouri.[1]

Second-seeded Missouri defeated #1 seed Oklahoma in the championship game, 98–86, to earn the conference's automatic bid to the 1989 NCAA tournament.

Bracket

Quarterfinals
Friday, March 10
Semifinals
Saturday, March 11
Championship
Sunday, March 12
         
1 #2 Oklahoma 95
8 Colorado 87
1 #2 Oklahoma 76
5 Iowa State 74
4 Oklahoma State 69
5 Iowa State 88
1 #2 Oklahoma 86
2 #10 Missouri 98
3 Kansas State 73
6 Kansas 65
3 Kansas State 83
2 #10 Missouri 88
7 Nebraska 70
2 #10 Missouri 98

References

  1. ^ "1988-89 Big 8 Conference Season Summary". sports-reference.com. Sports Reference. Retrieved March 31, 2019.
This page was last edited on 19 August 2023, at 06:12
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