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1988 United States Senate election in Wyoming

From Wikipedia, the free encyclopedia

1988 United States Senate election in Wyoming

← 1982 November 8, 1988 1994 →
 
Malcolmwallop.JPG
No image.svg
Nominee Malcolm Wallop John P. Vinich
Party Republican Democratic
Popular vote 91,143 89,821
Percentage 50.4% 49.6%

Wyoming Senate Election Results by County, 1988.svg
County Results

Wallop:      50-60%      60-70%      70-80%

Vinich:      50–60%      60–70%

U.S. Senator before election

Malcolm Wallop
Republican

Elected U.S. Senator

Malcolm Wallop
Republican

The 1988 United States Senate election in Wyoming took place on November 8, 1988. Incumbent Republican U.S. Senator Malcolm Wallop ran for re-election to a third term, and was narrowly re-elected, defeating the Democratic candidate John Vinich by a margin of a little over 1,300 votes.[1]

Major candidates

Democratic

  • John P. Vinich, Wyoming State Senator

Republican

General election

Despite being a reliably Republican state, Vinich, a Democrat, was able to impressively compete with Wallop. During the campaign, Wallop attacked Vinich as being a tax-and-spend liberal who was beholden to labor and anti-business.[1] Vinich, in turn, cited his "A" score he got from the National Rifle Association due to his votes in the Wyoming Legislature to counter Wallop's attacks, and possibly attract conservative voters.[1]

Results

General election results[2]
Party Candidate Votes %
Republican Malcolm Wallop (Incumbent) 91,143 50.37%
Democratic John P. Vinich 89,821 49.64%

See also

References

  1. ^ a b c "THE 1988 ELECTIONS: West; WYOMING". New York Times. November 9, 1988. Retrieved May 16, 2015.
  2. ^ "Our Campaigns -  WY US Senate Race - Nov 08, 1988". ourcampaigns.com. Retrieved May 10, 2015.
This page was last edited on 21 January 2020, at 04:49
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