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1976 United States presidential election in Kentucky

From Wikipedia, the free encyclopedia

United States presidential election in Kentucky, 1976

← 1972 November 2, 1976 1980 →
Carter cropped.jpg
Gerald Ford, official Presidential photo.jpg
Nominee Jimmy Carter Gerald Ford
Party Democratic Republican
Home state Georgia Michigan
Running mate Walter Mondale Bob Dole
Electoral vote 9 0
Popular vote 615,717 531,852
Percentage 52.8% 45.6%

Img.KY pre 1976.png
County Results

President before election

Gerald Ford

Elected President

Jimmy Carter

The 1976 United States presidential election in Kentucky took place on November 2, 1976, as part of the 1976 United States presidential election. Voters chose nine representatives, or electors, to the Electoral College, who voted for president and vice president.

Kentucky was won by Jimmy Carter (DGeorgia), with 52.75% of the popular vote. Carter defeated incumbent President Gerald Ford (RMichigan), who finished with 45.57% of the popular vote, and did so by winning all major demographic groups in the Commonwealth.[1] No third-party candidate amounted to 1% of the vote; American Party candidate Thomas Anderson came the closest with 0.71%.

Jimmy Carter went on to become the 39th president of the United States.[2] As of the 2016 presidential election, this is the last election in which Warren County, Hardin County, Madison County, Christian County, Taylor County, and Lincoln County voted for the Democratic candidate, and the last in which Boone County did not support the Republican candidate.


United States presidential election in Kentucky, 1976
Party Candidate Votes %
Democratic Jimmy Carter 615,717 52.75%
Republican Gerald Ford (inc.) 531,852 45.57%
American Thomas Anderson 8,308 0.71%
Independent Eugene McCarthy 6,837 0.59%
Write-In 4,428 0.38%
Total votes 1,167,142 100%


  1. ^ "Election Night 1976 ABC News Coverage".
  2. ^

This page was last edited on 13 October 2019, at 11:36
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