Stan Smith won the singles title at the 1970 Pepsi-Cola Masters. He defeated runner-up Rod Laver, although both had achieved the same number of wins.[1][2]
Round robin
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
 Rosewall |
 Franulović |
 Ashe |
Smith |
Laver |
 Kodeš
| |
| Ken Rosewall |
6–3, 6–3 | 6–3, 6–4 | 4–6, 5–6 | 6–5, 3–6, 5–6 | 6–5, 6–4 | |
| Željko Franulović |
3–6, 3–6 | 5–6, 6–3, 2–6 | 1–6, 6–5, 1–6 | 5–6, 6–3, 2–6 | 6–2, 3–6, 6–3 | |
| Arthur Ashe |
3–6, 4–6 | 6–5, 3–6, 6–2 | 3–6, 6–3, 6–5 | 3–6, 2–6 | 6–3, 4–6, 6–3 | |
| Stan Smith |
6–4, 6–5 | 6–1, 5–6, 6–1 | 6–3, 3–6, 5–6 | 4–6, 6–3, 6–4 | 6–3, 6–5 | |
| Rod Laver |
5–6, 6–3, 6–5 | 6–5, 3–6, 6–2 | 6–3, 6–2 | 6–4, 3–6, 4–6 | 6–4, 6–3 | |
| Jan Kodeš |
5–6, 4–6 | 2–6, 6–3, 3–6 | 3–6, 6–4, 3–6 | 3–6, 5–6 | 4–6, 3–6 |
Standings
| Player | RR W-L | Sets W-L | Games W-L | Standings |
|---|---|---|---|---|
| Stan Smith |
4–1 |
9–4 |
71–53 |
1
|
| Rod Laver |
4–1 |
9–4 |
69–55 |
2
|
| Ken Rosewall |
3–2 |
6–4 |
59–51 |
3
|
| Arthur Ashe |
3–2 |
6–7 |
58–53 |
4
|
| Željko Franulović |
1–4 |
5–9 |
55–70 |
5
|
| Jan Kodeš |
0–5 |
2–10 |
47–67 |
6
|
Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.
See also
References
- ^ John Barrett, ed. (1971). World of Tennis '71. London: Queen Anne Press. p. 134. ISBN 978-0-362-00091-7.
- ^ "Smith Bows to Ashe, but Wins Round-Robin Tennis in Tokyo". The New York Times. 15 December 1970.
External links
This page was last edited on 24 February 2022, at 02:18